On 12/29/21 12:01, Martin Rixham wrote:
What nonsense. I want to parse source code. ')' is not an uncommon line of
source code. It should work.
Unfortunately, you're asking for what is in general impossible. If the
left argument of ':' could be any string, then the grammar for 'expr'
would
What nonsense. I want to parse source code. ')' is not an uncommon line of
source code. It should work.
On Wed, 29 Dec 2021 at 19:52, Paul Eggert wrote:
> On 12/29/21 08:31, Davide Brini wrote:
> > I think you need to use '+' before the offending token
>
> Yes. That's a GNU extension. If you
ok I appreciate the explanation.
On Wed, 29 Dec 2021 at 20:58, Paul Eggert wrote:
> On 12/29/21 12:01, Martin Rixham wrote:
> > What nonsense. I want to parse source code. ')' is not an uncommon line
> of
> > source code. It should work.
>
> Unfortunately, you're asking for what is in general
I'm getting an error from the following:
[martin@fedora ~]$ expr ')' : '.*'
expr: syntax error: unexpected ')'
There also seems to be a similar problem with:
expr '(' : '.*'
Here's the version:
[martin@fedora ~]$ expr --version
expr (GNU coreutils) 8.32
Copyright (C)
On Wed, 29 Dec 2021 12:42:24 +, Martin Rixham
wrote:
> I'm getting an error from the following:
>
> [martin@fedora ~]$ expr ')' : '.*'
> expr: syntax error: unexpected ')'
>
> There also seems to be a similar problem with:
>
> expr '(' : '.*'
I think you need to use '+' before
On 12/29/21 08:31, Davide Brini wrote:
I think you need to use '+' before the offending token
Yes. That's a GNU extension. If you want to be portable to any POSIX
implementation, you can use this instead:
expr "X(" : '.*' - 1
A similar example is given in the POSIX spec for 'expr':
