On Tue, Aug 9, 2022 at 11:56 PM Paul Smith wrote:
> ...modifying the way all function arguments
> are parsed is something that needs to be carefully considered, if
> nothing else from a backward-compatibility standpoint.
agree.
i added an example to the manual of how to use variable to hide
On Tue, 2022-08-09 at 16:45 +0200, Gisle Vanem wrote:
> So does a "foo (arg1, arg2, arg3)" becomes one
> argument due to the parenthesis or something?
I agree it's strange. I'm not sure I agree with the change proposed in
the patch in the Savannah bug: modifying the way all function arguments
On Tue, Aug 9, 2022 at 10:48 AM Gisle Vanem wrote:
Thanks for your report.
See here https://savannah.gnu.org/bugs/index.php?62881
regards, Dmitry
Hello folks.
I have a question regarding parenthesis
in GNU-make macros. Like in:
msg = @echo "$(1)"
ptest_1:
$(call msg, foo (arg1, arg2, arg3))
ptest_2:
$(call msg, foo, arg1, arg2, arg3)
A 'make ptest_1' shows:
foo (arg1, arg2, arg3)
and
