Re: [ccp4bb] Fo-Fo Difference Map

2010-05-04 Thread Ian Tickle
Dale,

On Tue, May 4, 2010 at 12:19 AM, Dale Tronrud det...@uoxray.uoregon.edu wrote:
  The greater the difference in cell constants the greater the noise
 in the map.  I think the high resolution cutoff for the maps should
 be

    2 A delta/(A+delta)

 where A is the cell edge with the largest change, and delta is the
 amount of change (in Angstrom).  Basically a 1A change for a 100A
 edge would require a 2A resolution limit.  A 5A change would imply
 a 10A cutoff and a very boring map.

I think this estimate may be a little over-optimistic.  Crick 
Magdoff (1956, Acta Cryst.9, 901–908) calculated that for a 100Å cubic
unit cell a 0.5% change in all the cell dimensions, or a 0.5° rotation
of the molecule within the unit cell, would produce an average 15%
change in intensity, equivalent to a 7.5% average change in F, for
data to 3Å resolution.  So your 1% change in cell  at 2Å would give ~
22.5% average change in F, just from the non-isomorphism effects.  For
an Fo-Fc map, given that measurement errors are typically ~ 4 or 5% in
F, you need to have the average difference due the ligand or heavy
atom at least 3 times the noise level at the bare minimum, say at
least 12%, and indeed we see average differences (i.e. partial Fc) due
to a soaked ligand in the range 10-20%.  For an Fo-Fo map the noise
level is multiplied by sqrt(2) since you have 2 lots of measurement
errors, so you have 6-8% average experimental error in Fo-Fo.  Now
clearly if you have experimental errors of ~ 7% plus non-isomorphism
errors of 22.5% and you're looking for a signal of 15% due to the
ligand then you have a problem!  It implies you need to reduce the
non-isomorphism errors by a factor of at least 3, i.e. to = 0.3%
change in cell at 2Å.  Such a stringent requirement, which is
virtually impossible to achieve for frozen/soaked crystals (freezing 
soaking can easily induce  1% and sometimes  5% change), is surely
the reason that Fo-Fo maps never caught on!

One objection to this that I've seen is that Fo-Fc differences include
errors due to the model, say ~ 20% (assuming that's the R factor),
which Fo-Fo differences clearly do not.  However the point is that
this 20% contribution from the model error is spread throughout the
cell, not just at the ligand site, since it arises from co-ordinate 
B factor errors, disorder etc in all atoms, of which the ligand makes
up a very small fraction, so the contribution to this from errors in
the ligand parameters are likely to be negligible (adding the ligand
has a negligible effect on the R factor!).  In contrast the ~ 5%
experimental error in Fo-Fc, or ~ 7% + non-isomorphism error for
Fo-Fo, contribute roughly equally to the error in the density over the
whole cell.

Cheers

-- Ian


[ccp4bb] Post-doctoral fellow/scientist position at Karolinska Institutet

2010-05-04 Thread Gunter Schneider
Postdoctoral Position in Structural Enzymology of Bacterial Pathogens

A postdoctoral position is available for a highly motivated individual 
at the Department of Medical Biochemistry  Biophysics, Karolinska 
Institutet, Stockholm, Sweden. The candidate will join on-going 
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The project includes recombinant production of bacterial protein 
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---
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Department of Medical Biochemistry  Biophysics
Scheelevägen 2
Karolinska Institutet, 
S-171 77 Stockholm, Sweden
Phone: +46 8 5248 7675 , mobile phone: 0733 342 877 FAX: +46-8-32 76 
26 
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Re: [ccp4bb] Fo-Fo Difference Map

2010-05-04 Thread Dale Tronrud
   Ian's analysis is, as usual, much more sophisticated then my little
back-of-the-envelope calculation.  I would like to make one philosophical
note:  The non-isomorphism between the two crystals is not noise in the
Fo-Fo map, it is the whole point.  Sometimes the non-isomorphism is
dominated by the direct effects of the presence of a compound binding to
the protein (for instance) but other times by the large scale changes
in orientation of the domains of the protein in response to that compound.

   If your protein undergoes large scale motion upon binding and you are
interested in those motions then the Fo-Fo map will show them to you,
even though the small changes directly caused by the compound might
be difficult to discern.  If the protein doesn't have domain motions
then you are likely to see very interesting, specific, motions of
side chains and solvent around the binding site.  If you are not
interested by the major non-isomorphism of your pair of crystals you
will have to find some way to filter out the boring non-isomorphism
from the interesting non-isomorphism.  This will require a model
and the potential for model bias.  Very often this cannot be avoided.

   The variability of cell constants after freezing is a property of
the protein, not intrinsic to the freezing process itself.  With my
favorite protein the cell constants are very consistent after freezing
and I can calculate Fo-Fo maps that show great detail.

   Perhaps Fo-Fo maps would be more popular if they weren't so cumbersome
to calculate in the CCP4 world.

Dale Tronrud

On 05/04/10 04:48, Ian Tickle wrote:
 Dale,
 
 On Tue, May 4, 2010 at 12:19 AM, Dale Tronrud det...@uoxray.uoregon.edu 
 wrote:
  The greater the difference in cell constants the greater the noise
 in the map.  I think the high resolution cutoff for the maps should
 be

2 A delta/(A+delta)

 where A is the cell edge with the largest change, and delta is the
 amount of change (in Angstrom).  Basically a 1A change for a 100A
 edge would require a 2A resolution limit.  A 5A change would imply
 a 10A cutoff and a very boring map.
 
 I think this estimate may be a little over-optimistic.  Crick 
 Magdoff (1956, Acta Cryst.9, 901–908) calculated that for a 100Å cubic
 unit cell a 0.5% change in all the cell dimensions, or a 0.5° rotation
 of the molecule within the unit cell, would produce an average 15%
 change in intensity, equivalent to a 7.5% average change in F, for
 data to 3Å resolution.  So your 1% change in cell  at 2Å would give ~
 22.5% average change in F, just from the non-isomorphism effects.  For
 an Fo-Fc map, given that measurement errors are typically ~ 4 or 5% in
 F, you need to have the average difference due the ligand or heavy
 atom at least 3 times the noise level at the bare minimum, say at
 least 12%, and indeed we see average differences (i.e. partial Fc) due
 to a soaked ligand in the range 10-20%.  For an Fo-Fo map the noise
 level is multiplied by sqrt(2) since you have 2 lots of measurement
 errors, so you have 6-8% average experimental error in Fo-Fo.  Now
 clearly if you have experimental errors of ~ 7% plus non-isomorphism
 errors of 22.5% and you're looking for a signal of 15% due to the
 ligand then you have a problem!  It implies you need to reduce the
 non-isomorphism errors by a factor of at least 3, i.e. to = 0.3%
 change in cell at 2Å.  Such a stringent requirement, which is
 virtually impossible to achieve for frozen/soaked crystals (freezing 
 soaking can easily induce  1% and sometimes  5% change), is surely
 the reason that Fo-Fo maps never caught on!
 
 One objection to this that I've seen is that Fo-Fc differences include
 errors due to the model, say ~ 20% (assuming that's the R factor),
 which Fo-Fo differences clearly do not.  However the point is that
 this 20% contribution from the model error is spread throughout the
 cell, not just at the ligand site, since it arises from co-ordinate 
 B factor errors, disorder etc in all atoms, of which the ligand makes
 up a very small fraction, so the contribution to this from errors in
 the ligand parameters are likely to be negligible (adding the ligand
 has a negligible effect on the R factor!).  In contrast the ~ 5%
 experimental error in Fo-Fc, or ~ 7% + non-isomorphism error for
 Fo-Fo, contribute roughly equally to the error in the density over the
 whole cell.
 
 Cheers
 
 -- Ian


[ccp4bb] Advice on Over-expressing and Purifying Metalloproteins

2010-05-04 Thread Buz Barstow
Dear all,

I am trying to purify a metalloprotein (a hydrogenase) using affinity 
chromatography.

I have produced two tagged versions of the enzyme: one with an N-terminal 6x 
histidine affinity tag, and the other with a C-terminal 6x his-tag. The tagged 
proteins are both tied to an IPTG-inducible promoter.

When trying to express and purify the N-terminal tagged protein, I have found 
that almost all of the expressed protein goes into inclusion bodies when the 
culture is grown at 37 or at 30 degrees C. When the culture is grown at 20 
degrees C, a small amount of protein can be found in the cell extract. 

Unfortunately, as the enzyme has several oxygen-sensitive metal clusters, we do 
not believe that the protein can be refolded from the inclusion bodies.

Could you offer some advice on how to express and purify this protein and 
reduce the quantity of protein found in inclusion bodies?

Thanks! and all the best,

--Buz


[ccp4bb] Symposium Celebration of Greg Petsko and Dagmar Ringe

2010-05-04 Thread Raji Edayathumangalam

Dear CCP4bbers,

On September 4, 1980, Prof. Dagmar Ringe and Prof. Greg Petsko of MIT  
entered into an official scientific collaboration, and the scientific  
community has never been the same. Greg and Dagmar have jointly  
trained over 120 graduate students and postdocs and countless  
undergraduates in the past 29 years, and many of you might have worked  
with a student, postdoc, PhD advisor or postdoc mentor who previously  
either trained in or collaborated with the Petsko-Ringe lab. Now, 30  
years later, the members of the Petsko-Ringe lab are holding a  
symposium at Brandeis University in honor of their combined lifetimes  
of achievement.


The symposium and celebration is titled, From Sequence to  
Consequence: Celebrating 30 Years of Science with Dagmar Ringe and  
Greg Petsko.  Read more about the symposium at:

http://www.bio.brandeis.edu/PRSymposium2010/

While the symposium is a lab reunion of sorts for all the former and  
current students, postdocs, staff and collaborators of the Petsko- 
Ringe lab, we invite everyone from the structural community to take  
part in the celebration by posting congratulatory messages for Greg  
Petsko and Dagmar Ringe on our online Message Board.


Please post your HEARTY GREETINGS for Greg and Dagmar at:
http://prsymposium2010.blogspot.com/2010/05/celebration-of-dynamic-duo.html

Please could you circulate this email to colleagues who do not  
subscribe to CCP4BB.


With Warm Regards,
Members of the Petsko-Ringe Lab

---
Raji Edayathumangalam
Joint Research Fellow
Harvard Medical School/
Brigham and Women's Hospital
Brandeis University


Re: [ccp4bb] Advice on Over-expressing and Purifying Metalloproteins

2010-05-04 Thread Lieh Yoon Low
Buz,

How big is the protein? How many metal binding sites are there? Do you know 
what metal it should bind? What is your media?

I am assuming it is a zinc binding protein, some zinc binding protein will not 
fold without enough zinc in the media. Perhaps you should not rule out 
refolding.

ray
USF


On May 4, 2010, at 5:11 PM, Buz Barstow wrote:

 Dear all,
 
 I am trying to purify a metalloprotein (a hydrogenase) using affinity 
 chromatography.
 
 I have produced two tagged versions of the enzyme: one with an N-terminal 6x 
 histidine affinity tag, and the other with a C-terminal 6x his-tag. The 
 tagged proteins are both tied to an IPTG-inducible promoter.
 
 When trying to express and purify the N-terminal tagged protein, I have found 
 that almost all of the expressed protein goes into inclusion bodies when the 
 culture is grown at 37 or at 30 degrees C. When the culture is grown at 20 
 degrees C, a small amount of protein can be found in the cell extract. 
 
 Unfortunately, as the enzyme has several oxygen-sensitive metal clusters, we 
 do not believe that the protein can be refolded from the inclusion bodies.
 
 Could you offer some advice on how to express and purify this protein and 
 reduce the quantity of protein found in inclusion bodies?
 
 Thanks! and all the best,
 
 --Buz


Re: [ccp4bb] Advice on Over-expressing and Purifying Metalloproteins

2010-05-04 Thread Peter Hsu
Buz,

Have you tried putting on a solubility tag, such as GST?

I've found some times using M9 to grow my proteins in can give more soluble 
protein, although yields are usually lower.

Best,
Peter