Hi there,
today I encountered the very same problem as described by Zoltan. We are
running a system with the Intel serverboard S2600CP and two E5-2620 Xeon
processors, with a total of 2 x 6 Cores with 2 threads each (resulting
in a total CPU count of 24).
Base system is a CentOS 6.3 with all
Hi All,
Trying to run fsck on a local linux raid partition gave the following.
[root@... /]# fsck.ext4 /dev/md0
e2fsck 1.41.12 (17-May-2010)
/dev/md0 has unsupported feature(s): 64bit
e2fsck: Get a newer version of e2fsck!
Odd as the server is 64bit running latest kernel and using
latest
Try this out to find out who complains the arch, strace fsck.ext4
/dev/md5. Post the output here that we can check more if it's from the
app or the kernel.
Banyan He
Blog: http://www.rootong.com
Email: ban...@rootong.com
On 2012-10-25 5:10 PM, Steve Brooks wrote:
Hi All,
Trying
I think it comes out from the app itself for the verification. The
question is if the soft raid supports by anyhow. Trying to build one
test box for it.
print_unsupp_features:
if (features[0] || features[1] || features[2]) {
int i, j;
__u32 *mask = features, m;
On Thu, 25 Oct 2012, Banyan He wrote:
I think it comes out from the app itself for the verification. The
question is if the soft raid supports by anyhow. Trying to build one
test box for it.
print_unsupp_features:
if (features[0] || features[1] || features[2]) {
int i, j;
Send CentOS-announce mailing list submissions to
centos-annou...@centos.org
To subscribe or unsubscribe via the World Wide Web, visit
http://lists.centos.org/mailman/listinfo/centos-announce
or, via email, send a message with subject or body 'help' to
I am looking at using grubby. My command is:
grubby --grub --title CentOS (2.6.32.60)
--add-kernel=/boot/vmlinuz-2.6.32.60 --initrd=/boot/initrd-2.6.32.60.img
--args=ro root=LABEL=/ noapic --make-default
my etc/grub.conf file after running the command is:
title CentOS (2.6.32.60)
kernel
I am about to set up a computer with Centos 6 that I'll probably never see
again. I don't want to give out the root password, but I would like to have it
automatically and transparently update itself.
What is the best way to do this? I have been looking at webpages about yum-cron
and
On 10/25/2012 02:07 PM, Jerry Geis wrote:
I am looking at using grubby. My command is:
grubby --grub --title CentOS (2.6.32.60)
--add-kernel=/boot/vmlinuz-2.6.32.60
--initrd=/boot/initrd-2.6.32.60.img --args=ro root=LABEL=/ noapic
--make-default
my etc/grub.conf file after running the
Jerry Geis wrote:
On 10/25/2012 02:07 PM, Jerry Geis wrote:
I am looking at using grubby. My command is:
grubby --grub --title CentOS (2.6.32.60)
--add-kernel=/boot/vmlinuz-2.6.32.60
--initrd=/boot/initrd-2.6.32.60.img --args=ro root=LABEL=/ noapic
--make-default
my etc/grub.conf file
I am about to set up a computer with Centos 6 that I'll probably never see
again. I don't want to give out the root password, but I would like to
have it
automatically and transparently update itself.
What is the best way to do this? I have been looking at webpages about
yum-cron
and
I am about to set up a computer with Centos 6 that I'll probably never
see
again. I don't want to give out the root password, but I would like to
have it
automatically and transparently update itself.
What is the best way to do this? I have been looking at webpages about
yum-cron
and
On Thu, 25 Oct 2012, Frank Cox wrote:
To: centos@centos.org
From: Frank Cox thea...@melvilletheatre.com
Subject: [CentOS] Completely automatic yum updating on Centos 6
I am about to set up a computer with Centos 6 that I'll probably never see
again. I don't want to give out the root
If I run this:
find /path/to/files/ -type f -mtime -2 -name *.xml.gz
I get the expected results, files with modify time less than two days old.
But, if I run it like this, with the print0 flag:
find /path/to/files/ -print0 -type f -mtime -2 -name *.xml.gz
I get older files included as well.
On Thu, Oct 25, 2012 at 03:41:51PM -0500, Sean Carolan wrote:
If I run this:
find /path/to/files/ -type f -mtime -2 -name *.xml.gz
find /path/to/files/ -print0 -type f -mtime -2 -name *.xml.gz
Order of operations
find /path/to/files/ -type f -mtime -2 -name *.xml.gz -print0
--
rgds
On 25 October 2012 21:19, Keith Roberts ke...@karsites.net wrote:
On Thu, 25 Oct 2012, Frank Cox wrote:
To: centos@centos.org
From: Frank Cox thea...@melvilletheatre.com
Subject: [CentOS] Completely automatic yum updating on Centos 6
I am about to set up a computer with Centos 6 that I'll
Order of operations
find /path/to/files/ -type f -mtime -2 -name *.xml.gz -print0
Thanks!
___
CentOS mailing list
CentOS@centos.org
http://lists.centos.org/mailman/listinfo/centos
On Thu, 25 Oct 2012 21:19:24 +0100 (BST)
Keith Roberts wrote:
What about doing a ssh root login to the box from far away,
and then running yum check-update, to see what the
consequences of updating the box could do before
commiting to the update first?
As far as I know, while it will have
On Thu, Oct 25, 2012 at 5:19 PM, Frank Cox thea...@melvilletheatre.com wrote:
So if I plan to log into it remotely, I'll have to have it report its current
address to me on occasion.
Which probably wouldn't be a bad thing, anyway.
Or, if someone else will be logging in and you just don't
On Thu, 25 Oct 2012 17:50:49 -0500
Les Mikesell wrote:
Or, if someone else will be logging in and you just don't want to give
them root access, you could set up sudo access to a script that does a
'yum -y update' and then asks if they want to reboot.
I did consider that, but if it doesn't
on 10/25/2012 3:54 PM Frank Cox spake the following:
On Thu, 25 Oct 2012 17:50:49 -0500
Les Mikesell wrote:
Or, if someone else will be logging in and you just don't want to give
them root access, you could set up sudo access to a script that does a
'yum -y update' and then asks if they
21 matches
Mail list logo