I can do simply search and replace with sed.
However, I want to setup httpd.conf from a script
that changes the default / which is presently:
Directory /
Options FollowSymLinks
AllowOverride None
/Directory
and change it to the following:
Directory /
Order Deny,Allow
Deny from
On Thu, Mar 31, 2011, Jerry Geis wrote:
I can do simply search and replace with sed.
However, I want to setup httpd.conf from a script
that changes the default / which is presently:
While this can be done with sed, it's generally a lot easier to do with
python or perl, particularly when dealing
On 03/31/2011 05:25 AM, Jerry Geis wrote:
I can do simply search and replace with sed.
However, I want to setup httpd.conf from a script
that changes the default / which is presently:
Directory /
Options FollowSymLinks
AllowOverride None
/Directory
and change it to the
Hi all,
in a script if I have:
VERSION=3.2.0
I can do:
echo jj-$VERSION-jj
and get jj-3.2.0-jj
however if I do:
echo jj_$VERSION_jj
I get jj_
How do I get the $VERSION to work with the underscores like the dashes do.
Thanks,
Jerry
___
CentOS
On Fri, Jun 11, 2010 at 10:04 AM, Jerry Geis ge...@pagestation.com wrote:
Hi all,
in a script if I have:
VERSION=3.2.0
I can do:
echo jj-$VERSION-jj
and get jj-3.2.0-jj
however if I do:
echo jj_$VERSION_jj
I get jj_
How do I get the $VERSION to work with the underscores like the
however if I do:
echo jj_$VERSION_jj
I get jj_
How do I get the $VERSION to work with the underscores like the dashes
do.
echo jj_${VERSION}_jj
___
CentOS mailing list
CentOS@centos.org
http://lists.centos.org/mailman/listinfo/centos
How do I get the $VERSION to work with the underscores like
the dashes do.
echo JJ\_$VERSION\_JJ
***
This email and any files transmitted with it are confidential and
intended solely for the use of the individual or entity to
On Fri, Jun 11, 2010 at 10:04 AM, Jerry Geis ge...@pagestation.com wrote:
Hi all,
in a script if I have:
VERSION=3.2.0
I can do:
echo jj-$VERSION-jj
and get jj-3.2.0-jj
however if I do:
echo jj_$VERSION_jj
I get jj_
How do I get the $VERSION to work with the underscores like the
On Fri, Jun 11, 2010 at 10:04 AM, Jerry Geis ge...@pagestation.com
wrote:
in a script if I have:
VERSION=3.2.0
I can do:
echo jj-$VERSION-jj
and get jj-3.2.0-jj
however if I do:
echo jj_$VERSION_jj
I get jj_
How do I get the $VERSION to work with the underscores like the dashes
echo
From: m.r...@5-cent.us m.r...@5-cent.us
On Fri, Jun 11, 2010 at 10:04 AM, Jerry Geis
if I do: echo jj_$VERSION_jj
I get jj_
How do I get the $VERSION to work with the
underscores like the dashes
echo \_$VERSION\_
Or:echo jj_${VERSION}_jj
JD
-Original Message-
From: centos-boun...@centos.org
[mailto:centos-boun...@centos.org] On Behalf Of John Doe
Sent: Friday, June 11, 2010 10:50 AM
To: CentOS mailing list
Subject: Re: [CentOS] script question
From: m.r...@5-cent.us m.r...@5-cent.us
On Fri, Jun 11, 2010 at 10
I have this line:
ALSA=`aplay --version`
in a script. when I execute the script I get the message
line 187: --version: command not found
when I do aplay --version on the command line it works just fine.
What is happening here, --version is a valid command line option?
Thanks,
Jerry Geis wrote:
I have this line:
ALSA=`aplay --version`
in a script. when I execute the script I get the message
line 187: --version: command not found
$ echo $(aplay --version)
aplay: version 1.0.18 by Jaroslav Kysela pe...@perex.cz
t
I have this line:
ALSA=`aplay --version`
in a script. when I execute the script I get the message
line 187: --version: command not found
What's in line 187?
Do you really want to use backticks ` or should it be more like
ALSA='aplay --version' (apostrophes)? If you want to
On Thu, Jun 4, 2009 at 9:47 AM, Jerry Geisge...@pagestation.com wrote:
I have this line:
ALSA=`aplay --version`
in a script. when I execute the script I get the message
line 187: --version: command not found
when I do aplay --version on the command line it works just fine.
On Thu, Jun 04, 2009 at 10:11:37AM -0400, Jacques B. wrote:
head -n 188 your_script | tail -n 3
That will output lines 186-188 so that you have some context (in case
sed -n 186,188p your_script
:-)
--
rgds
Stephen
___
CentOS mailing list
On Thu, Jun 4, 2009 at 10:27 AM, Stephen Harrisli...@spuddy.org wrote:
On Thu, Jun 04, 2009 at 10:11:37AM -0400, Jacques B. wrote:
head -n 188 your_script | tail -n 3
That will output lines 186-188 so that you have some context (in case
sed -n 186,188p your_script
:-)
--
rgds
Stephen
Hi all,
I am trying to create a script that takes an entire file,
drops the first 19 characters from each line and creates a new file.
I am missing something easy but I am not seeing it.
Jerry
---
I tried the script below but did not work.
rm output.txt
cat test.txt | \
while read LINE
do
I am trying to create a script that takes an entire file,
drops the first 19 characters from each line and creates a new file.
I am missing something easy but I am not seeing it.
Jerry
---
I tried the script below but did not work.
rm output.txt
cat test.txt | \
while read LINE
do
Hello Jerry-
Simply change the line:
newline=`echo $LINE | cut -f 19-`
to this:
newline=`echo $LINE | cut -c 19-`
You want to cut based on 'c'haracters, not 'f'ields. :-)
Tim Nelson
Systems/Network Support
Rockbochs Inc.
(218)727-4332 x105
- Jerry Geis [EMAIL
On Wed, October 15, 2008 10:48 am, Jerry Geis wrote:
Hi all,
I am trying to create a script that takes an entire file,
drops the first 19 characters from each line and creates a new file.
I am missing something easy but I am not seeing it.
Jerry
---
I tried the script below but did not
Hi,
On Wed, Oct 15, 2008 at 10:48, Jerry Geis [EMAIL PROTECTED] wrote:
I am trying to create a script that takes an entire file,
drops the first 19 characters from each line and creates a new file.
newline=`echo $LINE | cut -f 19-`
What you want is cut -c 19- (-c as in characters) and
Filipe Brandenburger wrote:
Hi,
On Wed, Oct 15, 2008 at 10:48, Jerry Geis [EMAIL PROTECTED] wrote:
I am trying to create a script that takes an entire file,
drops the first 19 characters from each line and creates a new file.
newline=`echo $LINE | cut -f 19-`
What you want is cut -c
Jerry Geis wrote:
Hi all,
I am trying to create a script that takes an entire file,
drops the first 19 characters from each line and creates a new file.
[..]
test.txt is below
10-Oct-08 08:14 am 10
If this is the format of your data you could use awk to do the same
thing
cat filename |
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