ok this problem has been solved it is one of my directories acting up.
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>thanks, i'll work on it and get back to you
Thanks, I tried out your method, it generated the list and grouped them
according to their individual directories but it wont work for what i wanted to
use it for. What i intend to do is to pass the directory and file information
to a tag which mer
thanks, i'll work on it and get back to you
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try this:
#directory# list: #variables[directory]#
Azadi Saryev
Sabai-dee.com
http://www.sabai-dee.com/
On 23/09/2009 03:24, funsho wrote:
>
> #GetBoth.directory#
> #GetBoth.name#
>
>
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Want to reach the ColdFu
I am new to this, I have tons of directories that I am working on. I want to
output the files in each directory to a comma delimited list with each list
named after the directory containing the files. So far I have been able to
write a code that groups each files underneath each directory but
I am new to this, I have tons of directories that I am working on. I want to
output the files in each directory to a comma delimited list with each list
named after the directory containing the files. So far I have been able to
write a code that groups each files underneath each directory but
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