Simply create a date object for Jan 1 in the year you are testing. Then
add to it the ordinal (minus 1 I think). This will give you a date
object for the ordinal.
===
Raymond Camden, ColdFusion Jedi Master for Hire
Email:
Standard answer will be:
cfset myYear = 1999
cfset myDay = 182
cfset x = dateadd(d, myDay, createdate(myYear - 1, 12, 31))
Of course, those of us trying to liberate dates and allow them free access
into the numeric arena like the much simpler:
cfset myYear = 1999
cfset myDay = 182
cfset x =
cfscript
theYear = year(now()); // or whatever...
janEnd = 31;
febEnd = janEnd + 28;
if( isLeapYear(theYear) )
febEnd = febEnd + 1;
marEnd = febEnd + 31;
aprEnd = marEnd + 30;
mayEnd = aprEnd + 31;
junEnd = mayEnd + 30;
julEnd = junEnd + 31;
augEnd = julEnd + 31;
sepEnd = augEnd + 30;
: RE: Reverse Engineer DayOfYear Function?
Simply create a date object for Jan 1 in the year you are testing. Then
add to it the ordinal (minus 1 I think). This will give you a date
object for the ordinal.
===
Raymond Camden
Folks:
I am trying to obtain a date from the ordinal produced by the function
DayOfYear. In other words, does anyone know how to reverse engineer the
ordinal into a usable date? I would assume I'd need to pass the ordinal
and the year to some function to obtain a usable date. I can't
Simply create a date object for Jan 1 in the year you are testing. Then
add to it the ordinal (minus 1 I think). This will give you a date
object for the ordinal.
Oh jeez... I think I need some sleep...
I'm working on a pyramid scheme project ( not my idea ) that requires a
horrendous nested
Do you work at Microsoft? :)
-Original Message-
From: Bryan Love [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, September 04, 2002 3:56 PM
To: CF-Talk
Subject: RE: Reverse Engineer DayOfYear Function?
cfscript
theYear = year(now()); // or whatever...
janEnd = 31;
febEnd = janEnd + 28
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