Re: SQL Help

2009-08-26 Thread Brian Kotek
Yep, EXISTS will virtually always be faster, usually MUCH faster, than a correlated subquery, because a subquery is evaluated for EVERY ROW processed by the outer query. On Wed, Aug 26, 2009 at 12:43 AM, Mark Henderson shadefro...@gmail.comwrote: Brian Kotek wrote: WHERE NOT EXISTS should

Re: SQL Help

2009-08-25 Thread Kevin Roche
Mark, What DBMS are you using? If its SQL Server, I don't think what you want to do is possible other than how you have already done it. If you find another way to do it (with a join) I would also be interested to see that. Kevin Roche

Re: SQL Help

2009-08-25 Thread Mark Henderson
Kevin Roche wrote: Mark, What DBMS are you using? If its SQL Server, I don't think what you want to do is possible other than how you have already done it. If you find another way to do it (with a join) I would also be interested to see that. Kevin Roche Hi Kevin, Yes it's MS SQL.

Re: SQL Help

2009-08-25 Thread Kevin Roche
Mark, You might be right but I never got that to work myself, in MSSQL. An experiment you might try is to do that subquery separately in a different CFQUERY then plug in the retrieved value. Occasionally I have found that knid of trick is quicker. Kevin On Tue, Aug 25, 2009 at 11:49 AM, Mark

RE: SQL Help

2009-08-25 Thread Dawson, Michael
Try using an OUTER JOIN and specify the criteria in the JOIN statement ... FROM table1 LEFT OUTER JOIN table2 ON table1.col1 = table2.col1 AND {criteria goes here} ... Thanks, Mike -Original Message- From: Mark Henderson [mailto:shadefro...@gmail.com] Sent:

Re: SQL Help

2009-08-25 Thread Billy Cox
Try this: ... FROM tbl_ForSaleCategories C INNER JOIN ( tbl_RecentlyViewed RV INNER JOIN tbl_ForSale FS ON RV.ID = FS.ID ) ON C.ID = FS.Category_ID LEFT JOIN tbl_CoverSpecial CS ON RV.ID = CS.ID WHERE CS.ID IS NULL AND FS.Active = 1 ORDER BY Date_Viewed ASC;

Re: SQL Help

2009-08-25 Thread Mark Henderson
Thanks Billy and Michael (and Kevin). After some trial and error I managed to stumble upon solution (the outer join gave me results but not the expected set). cfquery name=qGetRecentRecord datasource=#request.dsn# SELECT TOP 1 RV.ID AS Rec_ID ,RV.Date_Viewed ,FS.ID

Re: SQL Help

2009-08-25 Thread Brian Kotek
WHERE NOT EXISTS should also work. On Tue, Aug 25, 2009 at 5:27 AM, Mark Henderson shadefro...@gmail.comwrote: Greetings from the chilly south, I have this query and it returns the expected result set, but I can't work out how to use a join instead of the NOT IN clause and I *know* that

Re: SQL Help

2009-08-25 Thread Mark Henderson
Brian Kotek wrote: WHERE NOT EXISTS should also work. Yes it does, and I knew about that method when using NOT IN, as it was a simple change to my original working query. What I didn't know, but now do after some googling, is that NOT EXISTS means it uses an index in the subquery as opposed

Re: SQL Help

2009-06-30 Thread Dominic Watson
Basically, the cfset sqlToRun = ... / is kind of redundant and negates the benefit of the cfquery tag. Put all you SQL inside the cfquery tag. cfqueryparam is only valid within cfquery tags. Dominic 2009/6/28 Jason Slack applesl...@gmail.com: CF 8.01 OS X. I have: cfset sqlToRun = INSERT

RE: SQL Help

2009-06-30 Thread Paul Alkema
[mailto:watson.domi...@googlemail.com] Sent: Tuesday, June 30, 2009 5:22 AM To: cf-talk Subject: Re: SQL Help Basically, the cfset sqlToRun = ... / is kind of redundant and negates the benefit of the cfquery tag. Put all you SQL inside the cfquery tag. cfqueryparam is only valid within cfquery

Re: SQL Help

2009-06-30 Thread Stephane Vantroyen
it's not good practice in ColdFusion to do this. I don't agree with that : sometimes you have to do multiple updates, inserts or else at the same time, depending on your process and some conditions; instead of doing multiple cfquery (and thus multiple db connections), it is sometimes cool

Re: SQL Help

2009-06-30 Thread Claude Schneegans
As Dominic said, putting the entire sql statement in as a variable in ColdFusion isn't necessary. Please, there IS a very good reason one would put an SQL statement in a variable: when using some tool to generate build queries for instance. I have many examples in my own CMS, like a report

Re: SQL Help

2009-06-30 Thread James Holmes
And with preserveSingleQuotes() you have to hope you're better at cleaning input than hackers are at writing SQL injection. And yes, we all know you're totally awesome at it; this response is for others who'd rather not make that bet. mxAjax / CFAjax docs and other useful articles:

RE: SQL Help

2009-06-30 Thread Paul Alkema
[mailto:s...@emakina.com] Sent: Tuesday, June 30, 2009 8:55 AM To: cf-talk Subject: Re: SQL Help it's not good practice in ColdFusion to do this. I don't agree with that : sometimes you have to do multiple updates, inserts or else at the same time, depending on your process and some conditions

Re: SQL Help

2009-06-30 Thread Claude Schneegans
And with preserveSingleQuotes() you have to hope you're better at cleaning input than hackers are at writing SQL injection. When I'm talking about a CMS, I'm talking about some tool some customers have paid for and that is only accessible by approved users with authentication. Now if they want

Re: SQL Help

2009-06-30 Thread Scott Brady
There's no reason you need a variable to do multiple updates in a single query statement. You can still put the SQL inside the query tags and, as you say, separate the statements with a semi-colon. Scott On Tue, Jun 30, 2009 at 6:55 AM, Stephane Vantroyens...@emakina.com wrote: I don't agree

RE: SQL Help

2009-06-30 Thread Paul Alkema
just use a stored proc and feed in the name. -Original Message- From: Scott Brady [mailto:dsbr...@gmail.com] Sent: Tuesday, June 30, 2009 9:52 AM To: cf-talk Subject: Re: SQL Help There's no reason you need a variable to do multiple updates in a single query statement. You can still put

Re: SQL Help

2009-06-30 Thread Dave Watts
When I'm talking about a CMS, I'm talking about some tool some customers have paid for and that is only accessible by approved users with authentication. Now if they want to hack and sabotage their own application they have paid for, it's their problem, and if it ever happens, they will pay

Re: SQL Help

2009-06-30 Thread James Holmes
Sure, as long as the CMS has no XSS attack points... mxAjax / CFAjax docs and other useful articles: http://www.bifrost.com.au/blog/ 2009/6/30 Claude Schneegans schneeg...@internetique.com:  And with preserveSingleQuotes() you have to hope you're better at cleaning input than hackers are at

Re: SQL Help

2009-06-30 Thread Claude Schneegans
Internal security problems are far more common than external ones. Within a large organization, not all users may be trustworthy. C'mon, if they are users and they have access to the system, if they go crazy, do they really need SQL injection to harm the system ? They can simply delete all

Re: SQL Help

2009-06-30 Thread James Holmes
With SQL injection they can delete what they don't have access to. With XSS they can do that while making it look like someone else did it. mxAjax / CFAjax docs and other useful articles: http://www.bifrost.com.au/blog/ 2009/6/30 Claude Schneegans schneeg...@internetique.com:  Internal

Re: SQL Help

2009-06-30 Thread Claude Schneegans
With XSS they can do that while making it look like someone else did it. Probably, but my clients barely know the difference between a computer and a toaster, and I spend more of my time explaining them that in order to press Ctrl, they must find a key on their keyboard with the letters Ctrl

RE: SQL Help

2009-06-30 Thread Paul Alkema
Message- From: Claude Schneegans [mailto:schneeg...@internetique.com] Sent: Tuesday, June 30, 2009 11:19 AM To: cf-talk Subject: Re: SQL Help With XSS they can do that while making it look like someone else did it. Probably, but my clients barely know the difference between a computer

RE: SQL Help

2009-06-30 Thread Justin Scott
If you don't take security in mind when writing applications it's just a matter of time before something bad happens. I can't tell you how many times I've been contacted by people who have had their site broken and need an emergency fix. I've made quite a bit of money fixing other people's

Re: SQL Help

2009-06-30 Thread Claude Schneegans
Also, you talk about this like your speaking of only internal applications or applications that could never go on a production environment. Indeed, we were talking about building SQL queries in a variable inside a Content management system. Of course, for parts of the site exposed to public,

Re: SQL Help

2009-06-30 Thread Dave Watts
C'mon, if they are users and they have access to the system, if they go crazy, do they really need SQL injection to harm the system ? They can simply delete all what they have access to, they can replace content by porn, whatever. Will CFQURYPARAM protect your application against that ?

Re: SQL Help

2009-06-28 Thread Charlie Griefer
if you're going to be generating your SQL like that, you'll need to wrap your final variable in preserveSingleQuotes(). so... cfquery name=addpersonaleventtome datasource=cf_WikiData #preserveSingleQuotes(sqlToRun)# /cfquery it will be pointed out to you (possibly before I even finish

Re: SQL Help

2009-06-28 Thread Jason Slack
Right I am switching everything to cfqueryparam as I read about SQL injection. Do you see my Invalid CFML construct found on line 22 at column 120. above though? I still dont. -Jason if you're going to be generating your SQL like that, you'll need to wrap your final variable in

Re: SQL Help

2009-06-28 Thread Matt Quackenbush
A) Always use cfqueryparam/. (Note the period.) B) When in doubt, use cfqueryparam/ anyways. (Note the period.) C) While preserveSingleQuotes() can be a useful tool at times, I would have a very difficult time thinking of a time where I would use it. D) Always use cfqueryparam/. (Note again,

Re: SQL help..

2008-10-29 Thread Peter Boughton
Just answered this on the SQL list: http://www.houseoffusion.com/groups/sql/thread.cfm/threadid:855 ~| Adobe® ColdFusion® 8 software 8 is the most important and dramatic release to date Get the Free Trial

Re: SQL help..

2008-10-29 Thread cf coder
I'm really greatful to you for the post. Just answered this on the SQL list: http://www.houseoffusion.com/groups/sql/thread.cfm/threadid:855 ~| Adobe® ColdFusion® 8 software 8 is the most important and dramatic release to date

Re: SQL Help

2008-09-16 Thread Gert Franz
Assuming your PK is named customerID you can do the following: SELECT mytable.lastname, mytable.firstname, mytable.city, mytable.state FROM mytable WHERE mytable.customerID in (select min(customerID) from mytable group by email) There is at least one problem in your query. The in () statement is

RE: SQL Help

2008-09-16 Thread Rick Faircloth
To view all your records with duplicate email addresses, you might try something like this: cfquery name=select_distinct_email datasource=dsn select distinct email from mytable /cfquery cfloop query=select_distinct_email cfquery

Re: SQL Help

2008-09-16 Thread Jim Wright
On Tue, Sep 16, 2008 at 8:58 AM, Jeff F [EMAIL PROTECTED] wrote: I've got a table (MySQL) with about 20k records. I'd like to be able to get all fields from the table with distinct email addresses. Essentially, I'm weeding out records with duplicate email addresses. What I'm trying does not

RE: SQL Help

2008-09-16 Thread Rick Faircloth
# #state#br br /cfoutput /cfloop -Original Message- From: Rick Faircloth [mailto:[EMAIL PROTECTED] Sent: Tuesday, September 16, 2008 9:42 AM To: CF-Talk Subject: RE: SQL Help To view all your records with duplicate email addresses, you might try something like

Re: SQL Help

2008-09-16 Thread Jeff F
Jim, At first glance that seems to work, however the recordcounts appear to be off. What I did was a simple query to find the total number of distinct email addresses: SELECT distinct mytable.email FROM mytable I get 19588 as a recordcount. When I run SELECT mytable.lastname,

Re: SQL Help

2008-09-16 Thread Jim Wright
On Tue, Sep 16, 2008 at 10:13 AM, Jeff F [EMAIL PROTECTED] wrote: SELECT distinct mytable.email FROM mytable I get 19588 as a recordcount. This number would include email addresses that are duplicated in the table (but only a count of 1 for each distinct address). SELECT

Re: SQL Help

2008-09-16 Thread Jeff F
Thanks Jim. Now I see. I guess what I'm looking for would be something like this then: SELECT mytable.lastname,mytable.email FROM mytable GROUP BY mytable.email HAVING distinct(mytable.email) Which of course does not work. When there are records with duplicate emails addresses, I need

Re: SQL Help

2008-09-16 Thread Judah McAuley
Are the other fields in your table the same when the email is the same? Meaning, are the records really duplicate? Or is it just the email that is duplicate and the other fields may have varying values for two rows that have the same email? If they do vary, do you care which of the duplicate rows

Re: SQL Help

2008-09-16 Thread C S
When there are records with duplicate emails addresses, I need to include one of them. So you are trying to display one record for each email address? You could try something like this. Not tested, but the idea is to select a single PK for each email. Then use a JOIN to display the details

Re: SQL Help

2008-09-16 Thread C S
You could try something like this. Not tested, but the idea is to select a single PK for each email. Then use a JOIN to display the details for those PK's. Note, the previous query assumes it does not matter which record is returned.

Re: SQL Help

2008-09-16 Thread Jeff F
The records are from contest entries. People can only enter with one email address. Some people entered multiple times, using the same email address. I need to get a record set used to pick a winner, including just one of the records from the duplicate email entries.

Re: SQL Help

2008-09-16 Thread C S
I need to get a record set used to pick a winner, including just one of the records from the duplicate email entries. If it does not matter which one, try the query I posted in my first response. The syntax is not tested, but it has the right concept.

Re: SQL Help

2008-09-16 Thread Jeff F
The records are from contest entries. People can only enter with one email address. Some people entered multiple times, using the same email address. I need to get a record set used to pick a winner, including just one of the records from the duplicate email entries.

Re: SQL Help

2008-09-16 Thread Justin Scott
The records are from contest entries. People can only enter with one email address. Some people entered multiple times, using the same email address. So, why all the complexity with joins and subqueries? Just... SELECT DISTINCT email FROM sometable then pick a winner from the list of

Re: SQL Help

2008-09-16 Thread C S
It also begs the question, if they were only supposed to have one entry per e-mail address, why wasn't there error checking or a constraint on the table to force this in the first place? True enough. I was thinking the same thing myself ;-)

Re: sql help NEQ

2008-04-03 Thread Paul Ihrig
ok i go it i think but it just looks so weird to me.. it looks back wards but works... SELECT DISTINCT TOP 100 PERCENT dbo.V_riprod_ZMATMAST.sap_partnum AS NEQnumb FROM dbo.V_riprod_ZMATMAST LEFT OUTER JOIN dbo.V_riprod_Specs_ZMATMAST_EQ ON

Re: sql help!!!!!!!!!!

2007-11-23 Thread Dave l
no dice cause it was 2am and didnt want to think about it no more Dunno if this is right, just woke up, but I'll take a stab at it. Looks like you need another join to the upsell table, then order by its sort by column first. SELECT brands.brand_id, brands.brand_name,

Re: sql help!!!!!!!!!!

2007-11-23 Thread Will Tomlinson
any good suggestions? Dunno if this is right, just woke up, but I'll take a stab at it. Looks like you need another join to the upsell table, then order by its sort by column first. SELECT brands.brand_id, brands.brand_name, brands.brand_logo, products.product_id, products.brand_id,

RE: SQL Help, please ...

2007-06-27 Thread Brad Wood
Let me get this straight, you want a report to summarize the number of installs by date and client. So client 1 ran 3 installs on 6/1 and 2 installs on 6/2. I believe you simply need to group by hostname, and then date and then use an aggregate function (count()) to add up the records in between

Re: SQL Help, please ...

2007-06-27 Thread Jochem van Dieten
[EMAIL PROTECTED] wrote: HostName, iDate, Package client1, 2007-06-01, Update1 client1, 2007-06-01, Update2 client1, 2007-06-01, Update3 client1, 2007-06-02, Update5 client1, 2007-06-02, NewApp client2, 2007-06-01, Update1 client2, 2007-06-01, Update2 client2, 2007-06-01, Update3

Re: SQL Help - Answered

2007-04-04 Thread [EMAIL PROTECTED]
Subject: Re: SQL Help - Answered I'm going to have to look at something. I'm still not getting what I anticipated. There are over 3700 records of which 1775 of them are distinct values for RATE. However, I am only getting values of 1 for COUNT(DISTINCT rate) as rateCount. I

Re: SQL Help

2007-04-03 Thread Greg Morphis
You need a group by in your query.. SELECT count(DISTINCT rate) as rateCount, rate FROMmyrates WHERE my_code = 385 and year = 2005 GROUP BY rate ORDER BY rate On 4/3/07, [EMAIL PROTECTED] [EMAIL PROTECTED] wrote: Why do the first two queries work and the last one fail? The only

Re: SQL Help - Answered

2007-04-03 Thread [EMAIL PROTECTED]
Thank you Greg Morphis wrote: You need a group by in your query.. SELECT count(DISTINCT rate) as rateCount, rate FROMmyrates WHERE my_code = 385 and year = 2005 GROUP BY rate ORDER BY rate On 4/3/07, [EMAIL PROTECTED] [EMAIL PROTECTED] wrote: Why do the

Re: SQL Help - Answered

2007-04-03 Thread Greg Morphis
No problem, if you want to know why take a look at aggregate functions, which is what count is, as well as others.. On 4/3/07, [EMAIL PROTECTED] [EMAIL PROTECTED] wrote: Thank you Greg Morphis wrote: You need a group by in your query.. SELECT count(DISTINCT rate) as rateCount, rate

Re: SQL Help - Answered

2007-04-03 Thread [EMAIL PROTECTED]
I'm going to have to look at something. I'm still not getting what I anticipated. There are over 3700 records of which 1775 of them are distinct values for RATE. However, I am only getting values of 1 for COUNT(DISTINCT rate) as rateCount. I was trying to find out how many records are

Re: SQL Help - Answered

2007-04-03 Thread Greg Morphis
can you provide a sample of your data and the way your table is designed (column name, type)? Thanks On 4/3/07, [EMAIL PROTECTED] [EMAIL PROTECTED] wrote: I'm going to have to look at something. I'm still not getting what I anticipated. There are over 3700 records of which 1775 of them are

Re: SQL Help - Answered

2007-04-03 Thread Josh Nathanson
that and see if you're any closer to what you want. -- Josh - Original Message - From: [EMAIL PROTECTED] [EMAIL PROTECTED] To: CF-Talk cf-talk@houseoffusion.com Sent: Tuesday, April 03, 2007 2:09 PM Subject: Re: SQL Help - Answered I'm going to have to look at something. I'm still

Re: SQL help

2006-04-03 Thread Rick Root
Rick Root wrote: I'm trying to figure out how to do something in SQL and I'm stumped. I solved this problem with a view, and it works great. Rick ~| Message: http://www.houseoffusion.com/lists.cfm/link=i:4:236815 Archives:

RE: SQL help (updated)

2005-08-17 Thread Dave.Phillips
That probably needs to be WHERE #idnumber# IN (MyColumn) Ian, Yes, I tried that. I had typoed my e-mail, but in my code I had the parenthesis. That's what give the invalid comparison error. It doesn't seem to recognize the field. Dave

RE: SQL help (updated)

2005-08-17 Thread Dave.Phillips
: Tuesday, August 16, 2005 4:37 PM To: CF-Talk Subject: Re: SQL help (updated) You realize that this is essentially a db design issue - right? The table shouldn't be holding lists of numbers - there should be a join table that does that job. Right? On 8/16/05, [EMAIL PROTECTED] [EMAIL PROTECTED

RE: SQL help Query of Queries (SOLVED) was (SQL help)

2005-08-17 Thread Dave.Phillips
To: CF-Talk Subject: Re: SQL help (updated) [EMAIL PROTECTED] wrote: Okay, I still need help, but I've resolve part of my problem. I'm able now to have the list of ID numbers in one field by themselves. So, my new field value (MyColumn) looks like this: '5,2,3,4,45,7' I still need a way

RE: SQL help (updated)

2005-08-16 Thread Dave.Phillips
Okay, I still need help, but I've resolve part of my problem. I'm able now to have the list of ID numbers in one field by themselves. So, my new field value (MyColumn) looks like this: '5,2,3,4,45,7' I still need a way using Query of Queries to extract only the records that have the

RE: SQL help (updated)

2005-08-16 Thread Ian Skinner
SELECT * FROM AllResults WHERE #idnumber# in MyColumn That probably needs to be WHERE #idnumber# IN (MyColumn) The values of an IN clause are supposed to be in parenthesis I believe. You may also need to do something about the quotes if they are

Re: SQL help (updated)

2005-08-16 Thread Jochem van Dieten
[EMAIL PROTECTED] wrote: Okay, I still need help, but I've resolve part of my problem. I'm able now to have the list of ID numbers in one field by themselves. So, my new field value (MyColumn) looks like this: '5,2,3,4,45,7' I still need a way using Query of Queries to extract only

Re: SQL help (updated)

2005-08-16 Thread Deanna Schneider
You realize that this is essentially a db design issue - right? The table shouldn't be holding lists of numbers - there should be a join table that does that job. Right? On 8/16/05, [EMAIL PROTECTED] [EMAIL PROTECTED] wrote: Okay, I still need help, but I've resolve part of my problem. I'm able

RE: SQL Help Please

2005-06-03 Thread Matthew Small
and companyid in (select distinct companyid Matthew Small Web Developer American City Business Journals 704-973-1045 [EMAIL PROTECTED] -Original Message- From: Jeff Fongemie [mailto:[EMAIL PROTECTED] Sent: Friday, June 03, 2005 10:20 AM To: CF-Talk Subject: SQL Help Please I've

RE: SQL Help Please

2005-06-03 Thread Dave Watts
I've got a query that I just can't get right. select * From companies where companyhide = 0 and companyid = (select distinct companyid From releases where date_entered = DATE_SUB(curdate (),INTERVAL 8 day) and date_entered = DATE_SUB

RE: SQL Help Please

2005-06-03 Thread Jeff Fongemie
and companyid in (select distinct companyid Matthew Small Web Developer American City Business Journals 704-973-1045 [EMAIL PROTECTED] That's it! I forget about in. I knew it was simple. Thanks! -jeff -Original Message- From: Jeff Fongemie [mailto:[EMAIL PROTECTED] Sent:

Re: SQL help - inserting a dynamic variable

2005-04-11 Thread Gareth Arch
You've more or less posted the answer. The method to use would be: INSERT INTO tblContactAddress(contactID,addressTypeID,address1, etc.) SELECT #contactIDValue#, ID, '#address1Value#',etc. FROM tblAddressType WHERE typename = 'General' Just make sure typename = 'General' will only return one

Re: SQL help - inserting a dynamic variable

2005-04-11 Thread Pete Ruckelshaus
Oh, so IOW I can only do that for one join table, not more than one? I have a couple of lookup columns that I'll be inserting... Pete On Apr 11, 2005 12:54 PM, Gareth Arch [EMAIL PROTECTED] wrote: You've more or less posted the answer. The method to use would be: INSERT INTO

Re: SQL help - inserting a dynamic variable

2005-04-11 Thread Gareth Arch
You should be able to join as many tables as you like (just as in a regular query). Just select the column names you need insert into tblthis (columnone, columntwo, columnthree) select c.dataone, d.datatwo, e.datathree from mycolumns c inner join mycolumnstwo d on (c.my_id = d.my_id) inner join

RE: SQL Help Needed

2004-11-19 Thread Pascal Peters
Subject: Re: SQL Help Needed Okay, here's what I've come up with we'll see how it goes... SELECT lanesID, subcategoryID, name, availability, price, srp, cost, description FROM dolls_backup INSERT INTO tblProducts(ProdName, ProdDesc, ProdSRP, ProdPrice, ProdCost, SubcatID) VALUES

Re: SQL Help Needed

2004-11-18 Thread Barney Boisvert
You'll have to check on the exact syntax, but something like this should work: INSERT INTO myTable (col1, col2, col3) SELECT col4, col5, col6 FROM otherTable The SELECT can be as complex as you want, as long as the columns it returns are the same number and type as what is needed by the INSERT

Re: SQL Help Needed

2004-11-18 Thread Donna French
Okay, here's what I've come up with we'll see how it goes... SELECT lanesID, subcategoryID, name, availability, price, srp, cost, description FROM dolls_backup INSERT INTO tblProducts(ProdName, ProdDesc, ProdSRP, ProdPrice, ProdCost, SubcatID) VALUES (dolls_backup.name, dolls_backup.description,

Re: SQL help needed fast

2004-11-08 Thread Thomas Chiverton
On Friday 05 Nov 2004 21:00 pm, Eric Creese wrote: lines is an int and this is MySQL Database. No issues with it in access or sql server Are those escaped ' meant to be there, or did it just happen when you pasted into your mail client ? What happens if you try the query by hand ? also in

Re: SQL help needed fast

2004-11-08 Thread Eric Creese
I am not sure by what you mean about escaping but that was the read out from the error page. SELECT * FROM p1_matrix WHERE display=apos;yesapos; AND lines = 1 ORDER BY Charht ; I have done this successfully with Access. I did notice that the datatype for charht is decimal and for lines it

Re: SQL help needed fast

2004-11-05 Thread Qasim Rasheed
which db, what is the datatype of lines? On Fri, 5 Nov 2004 14:34:46 -0600, Eric Creese [EMAIL PROTECTED] wrote: Can some one please tell me why this does not work? If you pass the url.inch variable it works fine. If you pass the url.line variable it fails with the following error. code is

RE: SQL help needed fast

2004-11-05 Thread Eric Creese
Subject: Re: SQL help needed fast which db, what is the datatype of lines? On Fri, 5 Nov 2004 14:34:46 -0600, Eric Creese [EMAIL PROTECTED] wrote: Can some one please tell me why this does not work? If you pass the url.inch variable it works fine. If you pass the url.line variable it fails

RE: SQL Help: nvarchar vs varchar

2004-10-12 Thread Micha Schopman
Microsoft SQL Server Help ... F1 .. Unicode Data Traditional non-Unicode data types in Microsoft(r) SQL Server(tm) 2000 allow the use of characters that are defined by a particular character set. A character set is chosen during SQL Server Setup and cannot be changed. Using Unicode data types,

RE: SQL help!

2004-08-12 Thread Bryan Love
PROTECTED] Sent: Tuesday, August 10, 2004 12:23 PM To: CF-Talk Subject: Re: SQL help! At 03:18 PM 8/10/2004, you wrote: This is probably basic, but my brain is not functioning at this point today... I need to compare two tables. They both contain customer numbers. One table mimics the other so

Re: SQL help!

2004-08-10 Thread Phillip Beazley
At 03:18 PM 8/10/2004, you wrote: This is probably basic, but my brain is not functioning at this point today... I need to compare two tables. They both contain customer numbers. One table mimics the other so the same data *should* be in each. It has come to my attention that there are orphans

RE: SQL help!

2004-08-10 Thread Jeff Waris
Quick and dirty .and it worked like a charm.. Thanks IN was where I shoulda been looking... Jeff [Todays Threads] [This Message] [Subscription] [Fast Unsubscribe] [User Settings] [Donations and Support]

Re: SQL help!

2004-08-10 Thread Claude Schneegans
SELECT * FROM table1 WHERE id NOT IN (SELECT id FROM table2) SELECT * FROM table2 WHERE id NOT IN (SELECT id FROM table1) Yes, and may be UNION the two in one: SELECT id FROM table1 WHERE id NOT IN (SELECT id FROM table2) UNION SELECT id FROM table2 WHERE id NOT IN (SELECT id FROM table1)

RE: SQL help!

2004-08-10 Thread Jeff Waris
That union worked well too... thanks! Jeff [Todays Threads] [This Message] [Subscription] [Fast Unsubscribe] [User Settings] [Donations and Support]

Re: SQL Help Please?

2004-07-30 Thread Cutter (CF-Talk)
Maybe I'm misunderstanding what you are trying to do, but try this Select count(Referer) as refcount From myTable Where Referer = #myUserID# Cutter Dave Phillips wrote: Hi guys, I hope this isn't too far off topic, but I'm stuck on an SQL issue and really need some help. I have a

RE: SQL Help Please?

2004-07-30 Thread Dave Phillips
94% of it for you? - http://honor.94percent.com _ From: Cutter (CF-Talk) [mailto:[EMAIL PROTECTED] Sent: Friday, July 30, 2004 8:31 PM To: CF-Talk Subject: Re: SQL Help Please? Maybe I'm misunderstanding what you are trying to do, but try this Select count(Referer) as refcount From myTable

RE: SQL Help Please?

2004-07-30 Thread Jeff Chastain
This is what you need ... SELECT DISTINCT(referer), COUNT(referer) FROM users GROUP BY referer -- Jeff _ From: Dave Phillips [mailto:[EMAIL PROTECTED] Sent: Friday, July 30, 2004 8:37 PM To: CF-Talk Subject: RE: SQL Help Please? Unfortunately, that will only give me the number

RE: SQL Help Please?

2004-07-30 Thread Dave Phillips
% of it for you? - http://honor.94percent.com _ From: Jeff Chastain [mailto:[EMAIL PROTECTED] Sent: Friday, July 30, 2004 8:39 PM To: CF-Talk Subject: RE: SQL Help Please? This is what you need ... SELECT DISTINCT(referer), COUNT(referer) FROM users GROUP BY referer -- Jeff _ From: Dave Phillips

RE: SQL Help

2004-06-16 Thread Pascal Peters
You are filtering on the enrollment table. This makes the left outer join useless. Try doing : WHERE e.EnrollmentDate BETWEEN '#fromDate#' AND '#toDate#' ORe.EnrollmentDate IS NULL And of course (Guess what or look at some other threads right now) -Original Message- From:

RE: SQL Help

2004-06-16 Thread Venable, John
yeah yeah, the cfqueryparam, i pulled this from SQL Analyzer, it chokes for some reason on that... :-) thanks, i'll check this out. JOhn -Original Message- From: Pascal Peters [mailto:[EMAIL PROTECTED] Sent: Wednesday, June 16, 2004 2:12 PM To: CF-Talk Subject: RE: SQL Help You

RE: SQL HELP!

2004-05-21 Thread Pascal Peters
Ascension day. -Original Message- From: Tony Weeg [mailto:[EMAIL PROTECTED] Sent: vrijdag 21 mei 2004 3:07 To: CF-Talk Subject: RE: SQL HELP! what holiday? tony [Todays Threads] [This Message] [Subscription] [Fast Unsubscribe] [User Settings]

RE: SQL HELP!

2004-05-20 Thread Matthew Walker
SELECT stuff.*, person1.*, person2.*, person3.* FROM( ( stuff LEFT JOIN persons AS person1 ON stuff.first_person_id = persons.person_id ) LEFT JOIN persons AS person2 ON stuff.second_person_id = persons.person_id ) LEFT JOIN persons AS person3 ON stuff.third_person_id = persons.person_id)

Re: SQL HELP!

2004-05-20 Thread brobborb
What if I wanted to add a WHERE clause? - Original Message - From: Matthew Walker To: CF-Talk Sent: Thursday, May 20, 2004 1:28 AM Subject: RE: SQL HELP! SELECT stuff.*, person1.*, person2.*, person3.* FROM( ( stuff LEFT JOIN persons AS person1 ON stuff.first_person_id

RE: SQL HELP!

2004-05-20 Thread Pascal Peters
AS person3 ON stuff.third_person_id = persons.person_id WHERE ... (your where clause here) -Original Message- From: brobborb [mailto:[EMAIL PROTECTED] Sent: donderdag 20 mei 2004 9:07 To: CF-Talk Subject: Re: SQL HELP! What if I wanted to add a WHERE clause? [Todays Threads

Re: SQL HELP!

2004-05-20 Thread brobborb
hey peter may i contact you off the list quick? - Original Message - From: Pascal Peters To: CF-Talk Sent: Thursday, May 20, 2004 4:22 AM Subject: RE: SQL HELP! Just add it after the FROM clause. Also keep in mind that if you use all * in the SELECT clause, you won't be able to access

RE: SQL HELP!

2004-05-20 Thread Philip Arnold
From: brobborb Now I want to return all the rows in the STUFF table, but to replace the last 3 fields with names in the PERSONS table. THe fields first_person_id, second_person_id, and third_person_id links to the person_id field in the table PERSONS. A good book to have on your desk

RE: SQL HELP!

2004-05-20 Thread Pascal Peters
Maybe too late, but you can. It's a holiday in Belgium, so I don't read my mail as often as on a work day. Pascal -Original Message- From: brobborb [mailto:[EMAIL PROTECTED] Sent: donderdag 20 mei 2004 11:24 To: CF-Talk Subject: Re: SQL HELP! hey peter may i contact you off

RE: SQL HELP!

2004-05-20 Thread Tony Weeg
what holiday? tony Tony Weeg sr. web applications architect navtrak, inc. [EMAIL PROTECTED] 410.548.2337 www.navtrak.net -Original Message- From: Pascal Peters [mailto:[EMAIL PROTECTED] Sent: Thursday, May 20, 2004 11:19 AM To: CF-Talk Subject: RE: SQL HELP! Maybe too late

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