On Jun 16, 2010, at 9:21 PM, Michael Gardner wrote:
On Jun 16, 2010, at 7:07 PM, ataggart wrote:
There's a disconnect between the function definition and the
datastructures used by the caller.
Either fix the data structure:
(def args [:bar 2 :baz [:quux]])
then use apply
Or change the
On Jun 25, 2:57 am, Chas Emerick cemer...@snowtide.com wrote:
This is fairly simple:
user= (defn foo [ {:as args}] [args])
#'user/foo
user= (def m {:a 5 :b 6})
#'user/m
user= (apply foo (- m seq flatten))
[{:a 5, :b 6}]
I'm not sure if it could be made easier, short of changing apply
On Wed, Jun 16, 2010 at 7:00 PM, Brian Carper briancar...@gmail.com wrote:
Given:
(defn foo [x {:as args}] [x args])
(foo 1 :bar 2 :baz [:quux])
= [1 {:bar 2, :baz [:quux]}]
If I have those rest-arguments already in a map, what's the most
elegant way to call foo with them?
(def args
There's a disconnect between the function definition and the
datastructures used by the caller.
Either fix the data structure:
(def args [:bar 2 :baz [:quux]])
then use apply
Or change the function definition to take a map:
(defn foo [x {:keys [bar baz]}]
...)
On Jun 16, 4:00 pm, Brian
On Jun 16, 2010, at 7:07 PM, ataggart wrote:
There's a disconnect between the function definition and the
datastructures used by the caller.
Either fix the data structure:
(def args [:bar 2 :baz [:quux]])
then use apply
Or change the function definition to take a map:
(defn foo [x
