Hi,
Given a sequence (x1, y1, x2, y2, x3, y3,...)
and another (z1, z2, z3, ...)
I want to interleave such that I get a sequence
(x1, y1, z1, x2, y2, z2, x3, y3, z3, ...)
What's the most succinct way to achieve this?
thanks
Paul
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Hi
Figured it out - Partition first sequence into two sequences then
interleave the three sequences.
Paul
On Thursday, June 27, 2013 11:37:40 AM UTC+1, Paul Meehan wrote:
Hi,
Given a sequence (x1, y1, x2, y2, x3, y3,...)
and another (z1, z2, z3, ...)
I want to interleave such that I
How about this?
(interleave (take-nth 2 xys) (take-nth 2 (rest xys)) zs)
Kind regards
Meikel
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given sequences xy and z
(flatten (interleave (partition 1 2 xy) (partition 1 2 (rest xy)) z))
works..
On Thursday, June 27, 2013 11:37:40 AM UTC+1, Paul Meehan wrote:
Hi,
Given a sequence (x1, y1, x2, y2, x3, y3,...)
and another (z1, z2, z3, ...)
I want to interleave such that I get
The solution
(flatten (interleave (partition 1 2 xy) (partition 1 2 (rest xy)) z))
works provided that none of the elements of xy or z are seqs.
For example if xy = [[1 3] [2 4] [3 7] [4 7]] and z= [[5] [6]] this
solution produces
(1 3 2 4 5 3 7 4 7 6).
The other proposal (interleave (take-nth
Try this. user (def xy [:x1 :y1 :x2 :y2 :x3 :y3])(as- xy _ (partition 2 _) (interleave _ [:z1 :z2 :z3]) (flatten _))#'user/xy(:x1 :y1 :z1 :x2 :y2 :z2 :x3 :y3 :z3)user 27.06.2013, 19:55, "Paul Meehan" paulchristophermee...@gmail.com:Hi,Given a sequence (x1, y1, x2, y2, x3, y3,...)and
One more solution.
user= (mapcat (fn [[x y] z] [x y z]) (partition 2 '(:x1 :y1 :x2 :y2 :x3
:y3)) '(:z1 :z2 :z3))
(:x1 :y1 :z1 :x2 :y2 :z2 :x3 :y3 :z3)
Y. Kohyama
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