On Thursday, July 17, 2014 8:49:12 AM UTC-4, empt...@gmail.com wrote:
Hi,
I have a list of epoch times which map to HTTP requests.
'(1405060202611
1405060201157
1405060201361
1405060201261
1405060200391
1405060201458
1405060201705
1405060201058
1405060205062
1405060201558
You could use frequencies:
user= (frequencies (map #(quot % 1000) epochs))
{1405060202 1, 1405060201 8, 1405060200 1, 1405060205 1}
--
You received this message because you are subscribed to the Google
Groups Clojure group.
To post to this group, send email to clojure@googlegroups.com
Note
As a start, you could use group-by with a function that squashes together
items that fall in the same second and then count the size of each value.
(reduce-kv (fn [c k v] (assoc c k (count v))) {} (group-by #(quot % 1000)
epochs))
;= {1405060205 1, 1405060200 1, 1405060201 8, 1405060202 1}
You need not reverse the list for counting requests per second.
If the data is in sorted order, you can start with any direction.
Take the first as the base and keep separating untill you get 1 second or X
units like 1000 milliseconds if your data is in milliseconds.
The count would be an item of
