Yes, I meant all primes under 200. Also, thanks for the tips, I'll
go fix the code right away.
Nebojsa
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Hi,
On Jan 26, 5:38 pm, twitter.com/nfma nuno.filipe.marq...@gmail.com
wrote:
You can use the sieve of Eratosthenes...
This actually is the sieve of Eratosthenes. If one really wants to go
out of one's way, one can investigate the sieve of Atkin (or other
improved variants) and the the various
hmm... I'm just learning clojure at the moment but by looking at code what I
see is:
1 - A collecting parameter called primes
2 - A test to verify if a number is a prime by calculating the reminder of
the division with all (or some) of the primes already found
3 - if a number is a prime then its
You are right. This isn't exactly sieve of Eratosthenes. My plan was
to implement it, but instead, I wrote this, because it was simpler (at
least for my knowledge of Clojure). But since it's too slow, I'll
transform it to real sieve of Eratosthenes, to check it's performance.
On Jan 27, 2:43 pm,
Hi,
On Jan 27, 2:43 pm, twitter.com/nfma nuno.filipe.marq...@gmail.com
wrote:
hmm... I'm just learning clojure at the moment but by looking at code what I
see is:
1 - A collecting parameter called primes
2 - A test to verify if a number is a prime by calculating the reminder of
the
Meikel,
while the end result is the same, the time complexity of the algorithm
is definately not. The exact difference is calculated in Melissa E.
O'Neill's paper, The Genuine Sieve of Eratosthenes [1], which also
includes some highly performant implementations of incremental
SoE-like prime
I was about to ask the same question on this list about this code
adapted from SICP section 3.5.3
pre
(defn pi-summands [n]
(cons (/ 1.0 n)
(lazy-seq (map - (pi-summands (+ n 2))
/pre
which causes a stack overflow when I run
(nth (pi-summands 1) 1)
but it looks like you have
Hi,
Am 27.01.2010 um 17:57 schrieb Michał Marczyk:
while the end result is the same, the time complexity of the algorithm
is definately not. The exact difference is calculated in Melissa E.
O'Neill's paper, The Genuine Sieve of Eratosthenes.
Dang. Details matter.
Sincerely
Meikel
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You
I've transformed algorithm to this:
(defn primes-bellow
calculates all primes bellow max
[max]
(loop [numbers (vec (range 2 max)) primes [] last-p 0]
(let [p (first (drop-while zero? (drop (dec last-p) numbers)))]
(if ( p (. Math
2010/1/27 Meikel Brandmeyer m...@kotka.de:
Dang. Details matter.
:-)
2010/1/27 Nebojsa Stricevic nebojsa.strice...@gmail.com:
I've transformed algorithm to this:
[ ... elided ... ]
And I think, that this is real SoE, and it can calculate sum of first
200 prime numbers in ~35 sec, on
On Tue, Jan 26, 2010 at 9:17 AM, Nebojsa Stricevic
nebojsa.strice...@gmail.com wrote:
Greetings,
I'm new to Clojure and working my way through Project Euler problems
for learning. I wrote function for calculating prime number below some
integer value max. But it doesn't work for large
Aha... I understand now. Thanks a lot for help. I will try to find
other solution. And yes, I'm not looking for too much help.
On Jan 26, 3:33 pm, Chouser chou...@gmail.com wrote:
On Tue, Jan 26, 2010 at 9:17 AM, Nebojsa Stricevic
nebojsa.strice...@gmail.com wrote:
Greetings,
I'm new to
There are a few options, but I suppose you don't want too many hints yet?
Oops..
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Hi,
On Jan 26, 3:17 pm, Nebojsa Stricevic nebojsa.strice...@gmail.com
wrote:
I'm new to Clojure and working my way through Project Euler problems
for learning. I wrote function for calculating prime number below some
integer value max. But it doesn't work for large numbers, causing
Hi Chris,
On Jan 26, 3:33 pm, Chouser chou...@gmail.com wrote:
Of course with this algorithm you *need* filter to be lazy, or
you'd never get past the first iteration of the loop.
I'm sorry. I have to ask.
Why?
Sincerely
Meikel
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On Tue, Jan 26, 2010 at 9:52 AM, Meikel Brandmeyer m...@kotka.de wrote:
Hi Chris,
On Jan 26, 3:33 pm, Chouser chou...@gmail.com wrote:
Of course with this algorithm you *need* filter to be lazy, or
you'd never get past the first iteration of the loop.
I'm sorry. I have to ask.
Why?
Hm,
Thanks a lot for help. I have much better understanding of laziness
now! But I guess I'll need to do some more math research, because both
algorithms provided here (my + removed laziness and the one from
Meikel) are too slow for calculating all primes below 200.
On Jan 26, 4:48 pm, Chouser
You can use the sieve of Eratosthenes...
2010/1/26 Nebojsa Stricevic nebojsa.strice...@gmail.com
Thanks a lot for help. I have much better understanding of laziness
now! But I guess I'll need to do some more math research, because both
algorithms provided here (my + removed laziness and the
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