On Mon, Sep 28, 2009 at 5:23 AM, Jarkko Oranen chous...@gmail.com wrote:
What happens is, when you call (mfloat + 1 2) the macro evaluates ('+
(float 1) (float 2)), ie. it calls the *symbol* + with parameters 1.0
and 2.0. Symbols, when used as functions, look themselves up in
whatever
Hi
2009/9/26 gerryx...@gmail.com gerryx...@gmail.com:
(defn float2 [f a b]
(f (float a ) (float b)))
(float2 + 1 2) = 3.0
(defmacro mfloat2 [f a b]
(f (float a) (float b)))
(mfloat2 + 1 2 ) = 2.0 ??? macro expend to last expression in
list,right?
This is because (mfloat2 + 1 2)
On Sep 28, 12:13 pm, Michael Wood esiot...@gmail.com wrote:
Hi
2009/9/26 gerryx...@gmail.com gerryx...@gmail.com:
(defn float2 [f a b]
(f (float a ) (float b)))
(float2 + 1 2) = 3.0
(defmacro mfloat2 [f a b]
(f (float a) (float b)))
(mfloat2 + 1 2 ) = 2.0 ??? macro
(defn float2 [f a b]
(f (float a ) (float b)))
(float2 + 1 2) = 3.0
(defmacro mfloat2 [f a b]
(f (float a) (float b)))
(mfloat2 + 1 2 ) = 2.0 ??? macro expend to last expression in
list,right?
(defmacro m2float2 [f a b]
`(~f (float ~a) (float ~b)))
(mfloat2 + 1 2) = 3.0
(defmacro
