This is probably a pretty newb question...sorry. I'm looking for the
idiomatic way to apply a seq of functions to other seqs. In other
words, a version of map that doesn't take a single f, but a seq of
them.
(map f c1 c2 ... cn)
= ((f c11 c21 ... cn1) (f c12 c22 ... cn2) ... (f c1m c2m ...
Hi,
(map (juxt f1 f2 f3) c1 c2 c3)
(map (apply juxt fs) c1 c2 c3)
(apply map (apply juxt fs) cs)
Sincerely
Meikel
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Or maybe on a second look:
(map apply fs c1 ... cn)?
(user= (map #(apply %1 %) [+ - *] [1 2 3] [1 2 3])
(2 0 9)
vs.
user= (map (juxt + - *) [1 2 3] [1 2 3])
([2 0 1] [4 0 4] [6 0 9])
Sincerely
Meikel
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On Fri, Feb 4, 2011 at 9:19 AM, Mike cki...@gmail.com wrote:
This is probably a pretty newb question...sorry. I'm looking for the
idiomatic way to apply a seq of functions to other seqs. In other
words, a version of map that doesn't take a single f, but a seq of
them.
(map f c1 c2 ... cn)
On Fri, Feb 4, 2011 at 10:11 AM, Ken Wesson kwess...@gmail.com wrote:
With juxt it's as Meikel wrote:
(defn supermap [fs cs]
(apply map (apply juxt fs) cs))
Or not. Hm, juxt documentation needs clarifying.
(defn supermap [fs cs]
(map apply fs (apply map vector cs)))
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On Feb 4, 10:11 am, Ken Wesson kwess...@gmail.com wrote:
This does it without using juxt:
(defn supermap [fs cs]
(map apply fs (apply map vector cs)))
This is really nice. Even handles infinity properly:
(supermap (repeat +) (range 3) (range 3))
= (0 2 4)
Thanks Ken and Meikel!
Mike
