Re: apply madness

Vectors are eager. So they'd need to be finite. Varargs/rest args can be infinite lazy sequences. So it is appropriate that they are just generic "seq" abstractions instead of something specific (and eager) like a vector. -- You received this message because you are subscribed to the Google

Re: apply madness

On Thursday, May 12, 2016 at 4:10:39 AM UTC-4, Michael Gardner wrote: > > There's no need to avoid `apply` altogether, IMO. You could do something > like this: > > (let [raw (list :a 1 :b 2 :c 3)] > (into {:raw raw} > (filter (comp even? second) > (apply hash-map

Re: apply madness

On Thursday, May 12, 2016 at 3:59:10 AM UTC-4, dennis wrote: > > A try: > > (let [raw (list :a 1 :b 2 :c 3)] > (->> raw >(partition 2) >(filter #(even? (second %))) >(map vec) >(into {}) >(merge {:raw raw}))) > > => {:b 2, :raw (:a 1 :b 2 :c 3)} >

Re: apply madness

There's no need to avoid `apply` altogether, IMO. You could do something like this: (let [raw (list :a 1 :b 2 :c 3)] (into {:raw raw} (filter (comp even? second) (apply hash-map raw BTW, `list` is pretty uncommon. Usually you'd just use a vector literal. And this is

Re: apply madness

A try: (let [raw (list :a 1 :b 2 :c 3)] (->> raw (partition 2) (filter #(even? (second %))) (map vec) (into {}) (merge {:raw raw}))) => {:b 2, :raw (:a 1 :b 2 :c 3)} 2016-05-12 15:46 GMT+08:00 hiskennyness : > This does what I want

apply madness

This does what I want but feels nooby-ish, as in "in a month I will do this without APPLY": (let [raw (list :a 1 :b 2 :c 3)] > (apply assoc {} > :raw raw > (apply concat >(filter #(even? (second %)) >(apply hash-map raw) >