On 11/08/17 20:15, Rolf Eike Beer wrote:
Am Donnerstag, 10. August 2017, 10:28:31 schrieb rle...@codelibre.net:
On 2017-08-10 09:50, Jones J.W. wrote:
I'm building my code on Linux using the g++ flags "-std=c++11". This
means that I must link with the libIce++11 libraries instead of
libIce.
Am Donnerstag, 10. August 2017, 10:28:31 schrieb rle...@codelibre.net:
> On 2017-08-10 09:50, Jones J.W. wrote:
> > I'm building my code on Linux using the g++ flags "-std=c++11". This
> > means that I must link with the libIce++11 libraries instead of
> > libIce.
> >
> > The FindIce module,
On 2017-08-10 10:28, rle...@codelibre.net wrote:
On 2017-08-10 09:50, Jones J.W. wrote:
I'm building my code on Linux using the g++ flags "-std=c++11". This
means that I must link with the libIce++11 libraries instead of
libIce.
The FindIce module, however as no provision for choosing these
On 2017-08-10 09:50, Jones J.W. wrote:
I'm building my code on Linux using the g++ flags "-std=c++11". This
means that I must link with the libIce++11 libraries instead of
libIce.
The FindIce module, however as no provision for choosing these
libraries thus resulting in unresolved symbols at