I’m just on fire today, aren’t I? Posted this on the wrong thread. Sorry for
the noise.
Charles
> On Aug 5, 2015, at 7:17 PM, Charles Srstka wrote:
>
>> On Aug 4, 2015, at 6:23 PM, Rick Mann wrote:
>>
>>> On Aug 4, 2015, at 16:22 , Quincey Morris
>>> wrote:
>>>
>>> On Aug 4, 2015, at 15:5
> On Aug 4, 2015, at 6:23 PM, Rick Mann wrote:
>
>> On Aug 4, 2015, at 16:22 , Quincey Morris
>> wrote:
>>
>> On Aug 4, 2015, at 15:58 , Rick Mann wrote:
>>>
>>> I'm curious why, and what the right approach might be?
>>
>> As to why, the problem is that instances of a type conforming to a p
> On Aug 4, 2015, at 16:22 , Quincey Morris
> wrote:
>
> On Aug 4, 2015, at 15:58 , Rick Mann wrote:
>>
>> I'm curious why, and what the right approach might be?
>
> As to why, the problem is that instances of a type conforming to a protocol
> aren’t necessarily objects. If you want them to
On Aug 4, 2015, at 15:58 , Rick Mann wrote:
>
> I'm curious why, and what the right approach might be?
As to why, the problem is that instances of a type conforming to a protocol
aren’t necessarily objects. If you want them to be, try declaring your protocol
like this:
protocol P: cla
I was hoping to use a protocol to define the objects I could put into an
NSOutlineView. Unfortunately, NSOutlineView has datasource methods that return
AnyObject, and I can't seem to return a variable of my protocol type as an
AnyObject.
I'm curious why, and what the right approach might be? If