How would I do an if statement in xsl were I am testing for the value of
an element? Example
xsl:if test=deviation = 1
.
where my incoming xml looks like this:
de deviation0/deviation
compleated-byN/A/compleated-by
Thanks for
You should ask [EMAIL PROTECTED] They are really good on xsl questions.
xsl:if test=deviation ='1'
Charlene
-Original Message-
From: Joydeep Bose [mailto:[EMAIL PROTECTED]
Sent: Thursday, June 26, 2003 12:49 PM
To: [EMAIL PROTECTED]; Tim Bachta
Subject: Re: xsl question
Hi,
I have an xml file as follows:
user
userid100/userid
/user
My XSL file is as follows:
xsl:template match=user
html
/body
a href=/cocoon/hello?userid=100Menu/a
/body
/html
/xsl:template
Now my xsl file has a static URL.But I need a dynamic
URL.Each and everytime when my userid changes
From: Kavitha Ramesh [mailto:[EMAIL PROTECTED]]
Please do not ask pure XSLT questions here. Take a look at XSLT specific
mail lists.
Hi,
I have an xml file as follows:
user
userid100/userid
/user
My XSL file is as follows:
xsl:template match=user
html
/body
a
From: Piroumian Konstantin [mailto:[EMAIL PROTECTED]]
From: Kavitha Ramesh [mailto:[EMAIL PROTECTED]]
Please do not ask pure XSLT questions here. Take a look at
XSLT specific mail lists.
Hi,
I have an xml file as follows:
user
userid100/userid
/user
My XSL file
*** REPLY SEPARATOR ***
On 26.03.2002 at 15:47 Argyn Kuketayev wrote:
As I've said
before, you can use an action to get params from whereever
you need then
expose them to sitemap (using returning map in an action).
Then you can
simply set those params in your trasformer
: Wednesday, March 27, 2002 6:22 AM
Subject: XSL-question: sort with parameter
Hi!
I passed a parameter to a stylesheet and I can get the value with
xsl:value-of select=$order-by/.
But I need to sort data by the value of the parameter like
xsl:sort select=$order-by order=ascending
Hi!
I passed a parameter to a stylesheet and I can get the value with
xsl:value-of select=$order-by/.
But I need to sort data by the value of the parameter like
xsl:sort select=$order-by order=ascending/.
But with this nothing happens and all other forms I tried also failed.
Does anyone know
Hi Axel,
You can use something like following:
xsl:sort select=child::node()[name()=$order]/
Best regards
Roman
Axel Honfi wrote:
Hi!
I passed a parameter to a stylesheet and I can get the value with
xsl:value-of select=$order-by/.
But I need to sort data by the value of the
It's not a very good solution if you have a lot of values for sort,
because you need to put one xsl:if tag for any possible value.
?xml version=1.0 encoding=ISO-8859-1?
xsl:stylesheet version=1.0
xmlns:xsl=http://www.w3.org/1999/XSL/Transform;
xsl:parameter name = sort/
xsl:template
Hi, this is a kind of offtopic question I think but anyway...
Is there a possibility to pass a parameter to a stylesheet?
I'd like to do the following:
Given a stylesheet, I'd like to include another but depending on a parameter
passed by some external source, say an xml page.
thanks in
Title: RE: XSL question
Yes.
There is a tutorial on this at cocooncenter.org:
http://www.cocooncenter.de/cc/documents/resources/request-params/index.html
-Tom
-Original Message-
From: Martin Mauri [mailto:[EMAIL PROTECTED]]
Sent: Monday, March 25, 2002 8:56 AM
Title: RE: XSL question
Hi Thomas,
That's a good answer, unfortunately I forgot to
point that I'm using Cocoon 1.8.2. Is there a solution for it?
thanks!
- Original Message -
From:
von Schwerdtner, Thomas (GXS,
FPI)
To: '[EMAIL PROTECTED]'
Sent: Monday, March 25
Title: RE: XSL question
Ah,
good point. I have no experience with pre 2.x Cocoon, so I don't know what
would work. I'm sure others around here can answer that
though.
-T
-Original Message-From: Martin Mauri
[mailto:[EMAIL PROTECTED]]Sent: Monday, March 25, 2002 9:07
AMTo
Hi,
you need to declare your parameter at the beginiing of the stylesheet :
xsl:param name=yourparam/
xsl:template match=/
Then in the body of your stylesheet, $yourparam gives you the value of the
parameter.
Good luck
Alex
Title: RE: XSL question
A while ago I made an XML (Cocoon 1.8)which
requested a parameter passed on from a form on a webpage. Maybe you can try
something similar for your XSL?
xsp:page
language="java"xmlns:sql="http://www.apache.org/1999/SQL"xmlns:xsp="http://www
[EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Monday, March 25, 2002 11:32 AM
Subject: Re: XSL question
Hi,
you need to declare your parameter at the beginiing of the stylesheet :
xsl:param name=yourparam/
xsl:template match=/
Then in the body of your stylesheet, $yourparam
Title: RE: XSL question
Dear Richard,
I understand what you say, but here the problem is
if I can get a parameter from an outside source, right?
- Original Message -
From:
Richard
Korthuis
To: [EMAIL PROTECTED]
Sent: Monday, March 25, 2002 11:32
AM
Subject
-Original Message-
From: Martin Mauri [mailto:[EMAIL PROTECTED]]
Sent: Monday, March 25, 2002 5:36 PM
To: [EMAIL PROTECTED]
Subject: Re: XSL question
Dear Alexandre,
Yes, I already know how to use params, but the point here is
that I need to
pass the param from an outside
can use
an
Action to create that param for you in sitemap then you can use it as
usual.
Regards,
Konstantin Piroumian
thanks!
- Original Message -
From: Alexandre Victoor [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Monday, March 25, 2002 11:32 AM
Subject: Re: XSL
Title: RE: XSL question
Hello,
What is this outside source? Are you calling the xml with
a param (http:///index.xml?param=something)
or are you passing this parameter in some other way?
Richard
- Original Message -
From:
Martin
Mauri
To: [EMAIL PROTECTED
Title: RE: XSL question
Ok, forget it anyway. Here goes another. Does
anyone remember how to define entities inside an xml file without the need of
declaring the use of a DTD?
thanks!
- Original Message -
From:
Richard
Korthuis
To: [EMAIL PROTECTED]
Sent: Monday
Try this:
?xml version=1.0 encoding=UTF-8?
!DOCTYPE root [
!ENTITY nbsp #160;
]
root
...
/root
Stefan
-Original Message-
From: Martin Mauri [mailto:[EMAIL PROTECTED]]
Sent: Monday, March 25, 2002 4:51 PM
To: [EMAIL PROTECTED]; Richard Korthuis
Subject: Re: XSL question
Ok
it worked good, thanks!
- Original Message -
From: Stefan Seifert [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Monday, March 25, 2002 1:11 PM
Subject: RE: XSL question
Try this:
?xml version=1.0 encoding=UTF-8?
!DOCTYPE root [
!ENTITY nbsp #160;
]
root
...
/root
Stefan
Kopie:
Thema: Re: XSL question
25.03.02
17:21
Bitte
antworten an
cocoon-users
Ok, forget it anyway. Here goes another. Does
Generator for reference)
Hope this helps
Regds,
Chiths
-Original Message-
From: Martin Mauri [mailto:[EMAIL PROTECTED]]
Sent: Monday, March 25, 2002 7:12 AM
To: [EMAIL PROTECTED]
Subject: Re: XSL question
Dear Konstantin,
That's fine, but what I need to do is to choose dinamically
.
Thanks,
-Mensaje original-
De: Simone Gianni [mailto:[EMAIL PROTECTED]]
Enviado el: lunes, 28 de enero de 2002 12:50
Para: [EMAIL PROTECTED]
Asunto: Re: Simple XSL question
At 12.37 28/01/2002 -0300, you wrote:
Hello,
How can I make a XSLT transformation of just a couple of elements
,
-Mensaje original-
De: Simone Gianni [mailto:[EMAIL PROTECTED]]
Enviado el: lunes, 28 de enero de 2002 12:50
Para: [EMAIL PROTECTED]
Asunto: Re: Simple XSL question
At 12.37 28/01/2002 -0300, you wrote:
Hello,
How can I make a XSLT transformation of just a couple of elements,
leaving
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