I am not sure I understand this implementation, but isn’t
>long s = convert(duration.getSeconds(), SECONDS);
needing to actually be
>long s = convert(duration.getSeconds(), NANOSECONDS);
so that s+n is in a common unit of measure?
Gregg
> On May 30, 2018, at 7:19 PM, Martin B
On Wed, May 30, 2018 at 7:43 PM, Gregg Wonderly wrote:
> I am not sure I understand this implementation, but isn’t
>
> >long s = convert(duration.getSeconds(), SECONDS);
>
> needing to actually be
>
> >long s = convert(duration.getSeconds(), NANOSECONDS);
>
> so that s+n is in a c
