Oded Padon wrote:
There is another reason why I think this has to be possible.
> It is possible using ctypes. Using ctypes with the same C++
> code written above (except for extern "C"), the following python code:
import ctypes;
lib_cpp = ctypes.CDLL('./test_cpp.so')
result = ctypes.c_int(0);
On 08/02/2010 01:46 PM, Oded Padon wrote:
import ctypes;
lib_cpp = ctypes.CDLL('./test_cpp.so')
result = ctypes.c_int(0);
lib_cpp.add(1, 2, ctypes.byref(result));
print result;
prints: "c_long(3)"
I do prefer however to use boost.python, as I would at a later stage want to
expose C++ classes t
nt result;
prints: "c_long(3)"
I do prefer however to use boost.python, as I would at a later stage want to
expose C++ classes to python, but exposing functions like the above is step one
for me.
Thanks again,
Oded
--- On Mon, 8/2/10, Nat Goodspeed wrote:
> From: Nat Goodspeed
>
Oded Padon wrote:
The C++ code is:
void add(int const a, int const b, int const& c)
{
c = a + b;
}
This doesn't even compile under g++ 4.0.1 (Mac):
error: assignment of read-only reference 'c'
I hope you're not using a compiler that accepts such code as legal?
I must emphasize that I w
