On a second test I found out that by resetting the out-vector to 0 I get
the expected output, regardless of direction. Does that make sense?
Am Donnerstag, 30. Mai 2019 22:25:59 UTC+2 schrieb Maxi Miller:
>
> That means that I don't have to create that matrix myself, but rather use
> the matrix
That means that I don't have to create that matrix myself, but rather use
the matrix I get from FE_Q_*::get_interpolation_matrix()?
The most interesting bug my code has at the moment is:
Q(a)->B(b): I get identical vectors, i.e. a == b
B(b)->Q(a): Vectors are not identical anymore, a != b
On 5/30/19 9:06 AM, 'Maxi Miller' via deal.II User Group wrote:
> I wanted to write some functions to convert my solution from using
> FE_Q-elements to FE_Bernstein-elements (and back). For that I wrote two
> functions, convert_feQ_to_feB() and convert_feB_to_feQ() (as listed in the
>
I wanted to write some functions to convert my solution from using
FE_Q-elements to FE_Bernstein-elements (and back). For that I wrote two
functions, convert_feQ_to_feB() and convert_feB_to_feQ() (as listed in the
attachment). When converting from FE_Q-elements to FE_Bernstein-elements, I
get
