On a second test I found out that by resetting the out-vector to 0 I get
the expected output, regardless of direction. Does that make sense?
Am Donnerstag, 30. Mai 2019 22:25:59 UTC+2 schrieb Maxi Miller:
>
> That means that I don't have to create that matrix myself, but rather use
> the matrix
That means that I don't have to create that matrix myself, but rather use
the matrix I get from FE_Q_*::get_interpolation_matrix()?
The most interesting bug my code has at the moment is:
Q(a)->B(b): I get identical vectors, i.e. a == b
B(b)->Q(a): Vectors are not identical anymore, a != b
Q(a)->B
On 5/30/19 9:06 AM, 'Maxi Miller' via deal.II User Group wrote:
> I wanted to write some functions to convert my solution from using
> FE_Q-elements to FE_Bernstein-elements (and back). For that I wrote two
> functions, convert_feQ_to_feB() and convert_feB_to_feQ() (as listed in the
> attachment
I wanted to write some functions to convert my solution from using
FE_Q-elements to FE_Bernstein-elements (and back). For that I wrote two
functions, convert_feQ_to_feB() and convert_feB_to_feQ() (as listed in the
attachment). When converting from FE_Q-elements to FE_Bernstein-elements, I
get t
Dear Bruno,
I agree to you. But I am dealing with the one dimensional rod theory and I
want to understand more complicated deformation modes, so I go for spacedim
3.
On Thu, May 30, 2019 at 6:41 PM Bruno Turcksin
wrote:
> Darius,
>
> Le jeu. 30 mai 2019 à 08:48, Darius Barreto a
> écrit :
> >
Darius,
Le jeu. 30 mai 2019 à 08:48, Darius Barreto a écrit :
> Thanks for the reply. By saying spacedim 3, I mean that the rod (being one
> dimensional) can deform in the three dimensional space.
Sure but does the deformation happens in a plan. If you bend a rod,
the deformation is in a plan so
Thanks for the reply. By saying spacedim 3, I mean that the rod (being one
dimensional) can deform in the three dimensional space.
On Thu, May 30, 2019 at 6:11 PM Bruno Turcksin
wrote:
> Darius,
>
> On Thursday, May 30, 2019 at 7:27:47 AM UTC-4, Darius Barreto wrote:
>
>> I am working with adapt
Darius,
On Thursday, May 30, 2019 at 7:27:47 AM UTC-4, Darius Barreto wrote:
> I am working with adaptive meshing for a one dimensional rod problem. The
> function* refine_and_coarsen_fixed_number *has not been instantiated for
> the class template parameters?.
>
No it hasn't. You can't do dim=
Hello everyone,
I am working with adaptive meshing for a one dimensional rod problem. The
function* refine_and_coarsen_fixed_number *has not been instantiated for
the class template parameters?.
I am getting the following error message.
/home/darius/elastic_deadtest_adaptive/dead_load_adaptive.
