Thank you all guys who replied here!!
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On 10/17/2016 03:36 AM, Daniel Arndt wrote:
From this symmetric gradient tensor, do we have one easy way to calculate
the following "the second invariant of rate-of-strain tensor"?
There is SymmetricTensor::second_invariant [1] which is defined as I2 = 1/2[
(trace sigma)^2 - trace
Jaekwang,
>From this symmetric gradient tensor, do we have one easy way to calculate
> the following "the second invariant of rate-of-strain tensor"?
>
There is SymmetricTensor::second_invariant [1] which is defined as I2 =
1/2[ (trace sigma)^2 - trace (sigma^2) ]
and
