when I switched out the sort|uniq -u and put in sort -u, it no longer
worked.
Sorry, I made a mistake. The pipe sort | uniq is equivalent to sort -u.
However, you use uniq -u, which differs from uniq without options :-)
i.e. check it out.. the above should give you the same number
of
a...@usp.br wrote:
Thanks for your message.
I find it useful
to have modprobe default to listing only modules that are NOT loaded
yet.
For the default use, when loading a module, this is the case.
Another issue is that some filenames have '-' in them, but the module
names have '_' in
Another issue is that some filenames have '-' in them, but the module
names have '_' in them.
This is a problem because the modules filenames are a mess. Some
filenames have an underscore '_' too.
Does the current solution filter out
duplicates due to the modulename and filename not
a...@usp.br wrote:
Another issue is that some filenames have '-' in them, but the module
names have '_' in them.
This is a problem because the modules filenames are a mess. Some
filenames have an underscore '_' too.
If you want to get
(all available mods) minus (already loaded
Package: bash-completion
Version: 1:2.0-1
Problem: The modules completion is performed by this function
_modules()
{
local modpath
modpath=/lib/modules/$1
COMPREPLY=( $( compgen -W $( command ls -RL $modpath 2/dev/null | \
sed -ne 's/^\(.*\)\.k\{0,1\}o\(\.[gx]z\)\{0,1\}$/\1/p' ) -- $cur
This is related to this bug, but more, this bug reminded me.
I wrote a completion routine for 'modprobe' that, in the module list,
only shows you the modules you have not loaded yet.
I know it is _possible_ to load an already-loaded module, again, but
in my own use, that's usually not the case
Thanks for your message.
I find it useful
to have modprobe default to listing only modules that are NOT loaded
yet.
For the default use, when loading a module, this is the case. The
command modprobe has also an -r option to unload the module,
and in this case it would complete to the
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