Is there an easy way of drawing an arc ? I have center, start and end
co-ordinates as XY.
From what I can see, I need to look at least 16 combinations to work out the
perimeter size depending in which quadrant the start and ends are in.
procedure Arc(X1, Y1, X2, Y2, X3, Y3, X4, Y4:
9:03 p.m.
To: delphi@delphi.org.nz
Subject: [DUG] Arc's
Is there an easy way of drawing an arc ? I have center, start and end
co-ordinates as XY.
From what I can see, I need to look at least 16 combinations to work out the
perimeter size depending in which quadrant the start and ends
January 2011 21:03
To: delphi@delphi.org.nz
Subject: [DUG] Arc's
Is there an easy way of drawing an arc ? I have center, start and end
co-ordinates as XY.
From what I can see, I need to look at least 16 combinations to work out
the perimeter size depending in which quadrant the start and ends
for these calculations, should you need them.
From: delphi-boun...@delphi.org.nz [mailto:delphi-boun...@delphi.org.nz] On
Behalf Of Marshland Engineering
Sent: Tuesday, 18 January 2011 21:03
To: delphi@delphi.org.nz
Subject: [DUG] Arc's
Is there an easy way of drawing an arc ? I have center, start and end
