The Style property is a set, so it can contain multiple values. For
example, a font could be both boldfaced and italicised.
In your case write: ToAll1.Font.Style := [fsBold];
Cheers,
John Christenhusz
> -Original Message-
> From: Alistair George [mailto:[EMAIL PROTECTED]]
> Sent: Wedn
Um I think it's a set... TFontStyle is the enumeration and TFontStyles is the set of
that
enumeration. So you need to add fsBold to the set of selected styles.
ToAll1.Font.Style := ToAll1.Font.Style + [fsBold];
I think there is an include notation include(ToAll1.Font.Style,fsBold);
but this on
>When I apply the above as
> ToAll1.Font.Style:=fsBold;
>I get a compiler error: incompatible types: Tfontstyles and Tfontstyle
>Whats the story??
Font.Style is a set. You need to do
ToAll1.Font.Style:=[fsBold];
Cheers,
Kuet-Fung.
TFontStyles is a set.
ToAll1.Font.Style is of type TFontStyles.
TFontStyle is only an item that may appear in the set TFontStyles.
fsBold is a TFontStyle.
[fsBold] is a set of TFontStyle and is therefore compatible with
TFontStyles.
Therefore use:
ToAll1.Font.Style := [fsBold];
OR
ToAll1.F
TfontStyles is a set of TFontStyle elements try using
ToAll1.Font.Style:=[fsBold];
Tim
> -Original Message-
> From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]On
> Behalf Of Alistair George
> Sent: Wednesday, March 31, 1999 9:14 AM
> To: Multiple recipients of list delphi
> Subject: [
