On Wed, 2009-03-25 at 12:07 -0400, Owen Taylor wrote:
So, basically, no I don't see a way that GNOME Shell coexists with
Compiz other than as two separate shells for the GNOME desktop.
And I think that coexistence is part of the problem with GNOME Shell
becoming the default GNOME interface.
2009/3/30 Ted Gould t...@gould.cx:
On Wed, 2009-03-25 at 12:07 -0400, Owen Taylor wrote:
So, basically, no I don't see a way that GNOME Shell coexists with
Compiz other than as two separate shells for the GNOME desktop.
And I think that coexistence is part of the problem with GNOME Shell
On Mon, 2009-03-30 at 20:23 +0100, Alberto Ruiz wrote:
2009/3/30 Ted Gould t...@gould.cx:
On Wed, 2009-03-25 at 12:07 -0400, Owen Taylor wrote:
So, basically, no I don't see a way that GNOME Shell coexists with
Compiz other than as two separate shells for the GNOME desktop.
And I think
On Mon, 2009-03-30 at 20:23 +0100, Alberto Ruiz wrote:
2009/3/30 Ted Gould t...@gould.cx:
On Wed, 2009-03-25 at 12:07 -0400, Owen Taylor wrote:
So, basically, no I don't see a way that GNOME Shell coexists with
Compiz other than as two separate shells for the GNOME desktop.
And I think
On Tue, Mar 31, 2009 at 3:23 AM, Alberto Ruiz ar...@gnome.org wrote:
2009/3/30 Ted Gould t...@gould.cx:
On Wed, 2009-03-25 at 12:07 -0400, Owen Taylor wrote:
So, basically, no I don't see a way that GNOME Shell coexists with
Compiz other than as two separate shells for the GNOME desktop.
And
I design a program.it's always loop until.
for example
#include stdio.h
#include stdlib.h
int main(int argc,char** argv)
{
while(1)
sleep(1);
return 0;
}
User logout desktop session,again login desktop session,this process still
exists but look like not run.
When logout desktop
I design a program.it's always loop until.
for example
#include
#include
int main(int argc,char** argv)
{
while(1)
sleep(1);
return 0;
}
User logout desktop session,again login desktop session,this process still
exists but look like not run.
When logout desktop session,system