[api-dev] Integer Division?

2005-12-14 Thread Felix E. Klee
How do I perform an integer division (e.g. 11 / 3 = 4) in OpenOffice Basic? -- Dipl.-Phys. Felix E. Klee Email: [EMAIL PROTECTED] (work), [EMAIL PROTECTED] (home) Tel: +49 721 8307937, Fax: +49 721 8307936 Linuxburg, Goethestr. 15A, 76135 Karlsruhe, Germany

Re: [api-dev] Integer Division?

2005-12-14 Thread Felix E. Klee
Am Mittwoch, 14. Dezember 2005 11:39 schrieb Eric MOREL: http://www.richhillsoftware.com/blog/archives/2005/06/xnumbers_011_no.html Do I really need an extra package just to do integer division? This operation is built into almost every programming language! -- Dipl.-Phys. Felix E. Klee

Re: [api-dev] Integer Division?

2005-12-14 Thread Eric MOREL
No I don't think so but perhaps you can see the macro code behind Xdivint(). Eric Felix E. Klee a crit: Am Mittwoch, 14. Dezember 2005 11:39 schrieb Eric MOREL: http://www.richhillsoftware.com/blog/archives/2005/06/xnumbers_011_no.html Do I really need an extra

Re: [api-dev] Integer Division?

2005-12-14 Thread Laurent Godard
Hi Felix, How do I perform an integer division (e.g. 11 / 3 = 4) in OpenOffice Basic? try this 11 \ 3 = 3 or fix(11/3) the rounding depends of what you need for me 11/3 is rounded to 3 Laurent -- Laurent Godard [EMAIL PROTECTED] - Ingénierie OpenOffice.org Indesko http://www.indesko.com

Re: [api-dev] Integer Division?

2005-12-14 Thread Stephan Wunderlich - Sun Germany - ham02 - Hamburg
Hi Felix, http://www.richhillsoftware.com/blog/archives/2005/06/xnumbers_011_no.html Do I really need an extra package just to do integer division? This operation is built into almost every programming language! does print cint(11/3) do what you want ? Regards Stephan --

Re: [api-dev] Integer Division?

2005-12-14 Thread Joerg Barfurth
Hi, How do I perform an integer division (e.g. 11 / 3 = 4) in OpenOffice Basic? Huh? IME the integer division operator (in languages where it exists) would produce 11 div 3 = 3, to match the modulus produced by the 'mod' operator (which does exist in StarBasic). That said, you can get

Re: [api-dev] Integer Division?

2005-12-14 Thread Felix E. Klee
Am Mittwoch, 14. Dezember 2005 12:11 schrieb Laurent Godard: 11 \ 3 = 3 I couldn't find documentation for this operator in the online help (1.1.3). How come? or fix(11/3) Well this probably uses a floating point number as an intermediary, which could introduce numerical errors. This is

Re: [api-dev] Integer Division?

2005-12-14 Thread Dieter Krogh - Sun Germany
Hi Felix, does Dim iResult as integer iResult = 11 \ 3 fit your needs? The \ operator would do the division with a whole number result. BTW, 11 / 3 would never result as 4. ;-) Best wishes Dieter Felix E. Klee wrote On 12/14/05 11:26,: How do I perform an integer division (e.g. 11 /

Re: [api-dev] Integer Division?

2005-12-14 Thread Andrew Douglas Pitonyak
Felix E. Klee wrote: Am Mittwoch, 14. Dezember 2005 12:11 schrieb Laurent Godard: 11 \ 3 = 3 I couldn't find documentation for this operator in the online help (1.1.3). How come? or fix(11/3) Well this probably uses a floating point number as an intermediary, which