Does this also mean that procedures like round, floor and ceiling will
produce exact integers even when given an inexact argument? I am not sure
this would be a good idea. For example consider:
Now (round #i1e200) - flonum of 64 bits.
But (inexact-exact (round #i1e200)) - exact integer of over 600
At Mon, 13 Dec 2010 16:43:58 +0100,
Jos Koot wrote:
Would we not have the same problem with 'rational?'.
All reals, both exact and inexact ones are rationals (for the obvious reason
that we cannot represent every irrational number in finite memory)
Would we not need the same distinction
-Original Message-
From: Vincent St-Amour [mailto:stamo...@ccs.neu.edu]
Sent: 13 December 2010 17:01
To: Jos Koot
Cc: 'Noel Welsh'; dev@racket-lang.org
Subject: Re: [racket-dev] (round), etc. in Typed Racket
At Mon, 13 Dec 2010 16:43:58 +0100,
Jos Koot wrote:
Would we not
See
http://bugs.racket-lang.org/query/?cmd=viewpr=11049
Shriram
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