Hi Ishara,
In Jaggery you can use try, catch with Log to log errors properly.
Following is an example.
var log = new Log();
try{
//do work
} catch (e) {
log.error(e) ; //logs the stack trace
print(e); // prints the stack trace
} finally{
//do final
}
Also you can use the properties of ex
Hi Ishara,
Are you sure? It works perfect for me. I tested both with and without
stringify method.
Could you show your code? Maybe I might have misunderstood your problem.
On Fri, Nov 20, 2015 at 1:21 PM, Ishara Cooray wrote:
> Thanks for the reply Lalanke. But *stringify() * results the same.
>
Thanks for the reply Lalanke. But *stringify() * results the same.
Ishara Cooray
Senior Software Engineer
Mobile : +9477 262 9512
WSO2, Inc. | http://wso2.com/
Lean . Enterprise . Middleware
On Fri, Nov 20, 2015 at 12:22 PM, Lalanke Athauda wrote:
> Hi Ishara,
> Try this one.
>
> var exceptionS
Hi Ishara,
Try this one.
var exceptionString = "Custom Message" + *stringify*(e);
Hope this solve your problem.
On Fri, Nov 20, 2015 at 11:57 AM, Ishara Cooray wrote:
> Hi,
>
> In Jaggerry If an exception is concatenated to a string it will
> concatenate only the message part but the stacktrac
Hi,
In Jaggerry If an exception is concatenated to a string it will concatenate
only the message part but the stacktrace is omited.
ex: var exceptionString = "Custom Message" + e;
This exceptionString does not have the stacktrace.
How can i get the exception with the stacktrace as a string in Ja