real ObtenerTipoCambio(date fecha)
{
str sfecha;
real ntipocambio = -1;
WebService ws;
;
try
{
sfecha = date2str(fecha, 321, 2, 3, 2, 3, 4);
ws = new
WebService("http://crux.bccr.fi.cr/bccr/TipoCambio.asmx?wsdl");
ntipocambio = ws.getTipoCambioVentaHistorico("Ricoh Lanier de Costa
Rica", sfecha);
}
catch
{
ntipocambio = -1;
}
return ntipocambio;
}
Regards,
RM.
--------------------------------------------------------------------------------
De: gonzalo_edo [mailto:[EMAIL PROTECTED]
Enviado el: Miércoles, 25 de Agosto de 2004 10:14 a.m.
Para: [EMAIL PROTECTED]
Asunto: [development-axapta] Web Service/XML
I execute the code to connect to an Web Service and this error is
returned:
Method 'MSSoapInit' in COM object of class 'MSSOAP.SoapClient'
returned error code 0x80020009 (DISP_E_EXCEPTION) which means:
WSDLReader:Loading of the WSDL file failed HRESULT=0x80070057 -
WSDLReader:XML Parser failed at linenumber 62, lineposition 19,
reason is: End tag 'span' does not match the start tag 'br'.
HRESULT=0x1.
This is the code I'm using:
str 3 user= 'GBS';
COM soapClient = new COM("MSSOAP.SoapClient");
WebService w = new WebService
("http://crux.bccr.fi.cr/bccr/TipoCambio.asmx");
print w.getTipoCambioVenta(user);
pause;
What am I doing wrong??
Does Axapta don't support .asmx Web Services??
I hope anybody has a solution to this...
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