http://d.puremagic.com/issues/show_bug.cgi?id=2871
Summary: Take assumes that R.opIndex(uint) returns an lvalue. Product: D Version: 2.029 Platform: PC OS/Version: Windows Status: NEW Severity: normal Priority: P2 Component: Phobos AssignedTo: bugzi...@digitalmars.com ReportedBy: dsim...@yahoo.com import std.range, std.algorithm; void main() { auto r = iota(0, 10, 1); assert(equal(r, [0, 1, 2, 3, 4, 5, 6, 7, 8, 9][])); r = iota(0, 11, 3); assert(equal(r, [0, 3, 6, 9][])); assert(r[2] == 6); } C:\dmd\windows\bin\..\..\src\phobos\std\range.d(1184): Error: this._input.opIndex(index) is not an lvalue C:\dmd\windows\bin\..\..\src\phobos\std\range.d(4): Error: template instance std.range.iota!(int,int,int) error instantiating This is caused by static if (isRandomAccessRange!(R)) ref ElementType!(R) opIndex(uint index) { enforce(_maxAvailable > index); return _input[index]; } in std.range. What is needed is some compile time reflection to determine whether a function returns by reference or value. --