On Tue, 09 Dec 2008 22:54:30 -0600, Ellery Newcomer wrote:
Does the following totally not make sense? I think it should work.
int[] a = new int[10];
a.length += 30;
Unfortunately, the .length property, like all properties, do not support
the 'op=' syntax. You have to do it the long way
Reply to Denis,
On Wed, 10 Dec 2008 03:24:48 +0300, Jarrett Billingsley
[EMAIL PROTECTED] wrote:
On Tue, Dec 9, 2008 at 7:00 PM, BCS [EMAIL PROTECTED] wrote:
final void add(T...)(T t)
If all the params are the same type, typesafe variadics are a more
efficient/less code-bloaty way to do
On Wed, 10 Dec 2008 19:31:47 +0300, BCS [EMAIL PROTECTED] wrote:
Reply to Denis,
On Wed, 10 Dec 2008 03:24:48 +0300, Jarrett Billingsley
[EMAIL PROTECTED] wrote:
On Tue, Dec 9, 2008 at 7:00 PM, BCS [EMAIL PROTECTED] wrote:
final void add(T...)(T t)
If all the params are the same type,
Ellery Newcomer wrote:
raymond wrote:
how to check if array key exist in array or not? for example
char[] [char[]] t;
t[tes1]=val1;
t[tes2]=val2;
t[tes3]=val3;
if (t[test1]) writefln(NONE);
if(test1 in t) writefln(exists);
Also useful:
char[] value;
if ( (value = test1
On Wed, Dec 10, 2008 at 5:31 PM, Weed [EMAIL PROTECTED] wrote:
code:
import std.stdio;
class MyClass
{
invariant uint a = 0;
}
void main()
{
static MyClass c = new MyClass;
writeln( c.a );
}
It's not the class member that wants static initialization, it's your
variable
Reply to Jarrett,
On Wed, Dec 10, 2008 at 5:31 PM, Weed [EMAIL PROTECTED] wrote:
code:
import std.stdio;
class MyClass
{
invariant uint a = 0;
}
void main()
{
static MyClass c = new MyClass;
writeln( c.a );
}
It's not the class member that wants static initialization, it's your
variable
Denis Koroskin пишет:
On Thu, 11 Dec 2008 01:31:32 +0300, Weed [EMAIL PROTECTED] wrote:
But my class does not contain data that need initialization and can be
created
in compile time
code:
import std.stdio;
class MyClass
{
invariant uint a = 0;
}
void main()
{
static MyClass c =
Jarrett Billingsley пишет:
On Wed, Dec 10, 2008 at 5:31 PM, Weed [EMAIL PROTECTED] wrote:
code:
import std.stdio;
class MyClass
{
invariant uint a = 0;
}
void main()
{
static MyClass c = new MyClass;
writeln( c.a );
}
It's not the class member that wants static initialization,
On Thu, 11 Dec 2008 02:13:58 +0300, Weed [EMAIL PROTECTED] wrote:
Denis Koroskin пишет:
On Thu, 11 Dec 2008 01:31:32 +0300, Weed [EMAIL PROTECTED] wrote:
But my class does not contain data that need initialization and can be
created
in compile time
code:
import std.stdio;
class MyClass
