Hi,
I would like to know if it's possible to pass the return of a
function as argument to another function as below:
import std.stdio;
auto foo(int x, int y){
writeln(x, y);
return 3, 4;
}
void main(){
foo(foo(1,2));
}
I would like to print:
1 2
3 4
PS: I tried
On 06/28/2013 11:07 AM, MattCoder wrote:
Hi,
I would like to know if it's possible to pass the return of a function
as argument to another function as below:
import std.stdio;
auto foo(int x, int y){
writeln(x, y);
return 3, 4;
}
void main(){
foo(foo(1,2));
}
I would like to
On Fri, 28 Jun 2013 20:07:23 +0200, MattCoder mattco...@hotmail.com
wrote:
Hi,
I would like to know if it's possible to pass the return of a function
as argument to another function as below:
import std.stdio;
auto foo(int x, int y){
writeln(x, y);
return 3, 4;
}
void
On Friday, 28 June 2013 at 19:39:41 UTC, Ellery Newcomer wrote:
However, they can return std.typecons.Tuple, so you could do
this:
auto foo(int i, int j) {
writeln(i, , j);
return tuple(3,4);
}
void main() {
foo(foo(1,2).field);
}
Hi Ellery,
Thanks for your help, it works
On Friday, 28 June 2013 at 19:43:37 UTC, Simen Kjaeraas wrote:
import std.stdio;
import std.typecons : tuple;
auto foo(int x, int y){
writeln(x, y);
return tuple(3, 4);
}
void main(){
foo(foo(1,2).tupleof);
}
Hi Simen,
Thanks for your help too, it worked!
However, they can return std.typecons.Tuple, so you could do this:
auto foo(int i, int j) {
writeln(i, , j);
return tuple(3,4);
}
void main() {
foo(foo(1,2).field);
}
field is deprecated in favor of expand
