On Monday, 28 January 2013 at 10:44:22 UTC, qznc wrote:
On Monday, 28 January 2013 at 03:16:24 UTC, cal wrote:
Is the 'typeof((int a){return z;})' getting it wrong here?
Do you really need the type? You could just use "auto".
auto dg = (int a) {return z;};
Yeah this is reduced from somethin
On Monday, 28 January 2013 at 03:16:24 UTC, cal wrote:
This fails:
void main() {
int z;
typeof((int a){return z;}) dg;
dg = (int a) {return z;};
}
Error: cannot implicitly convert expression (__lambda2) of type
int delegate(int a) nothrow @safe to int delegate(int a) pure
nothrow
On Monday, 28 January 2013 at 03:16:24 UTC, cal wrote:
This fails:
void main() {
int z;
typeof((int a){return z;}) dg;
dg = (int a) {return z;};
}
Error: cannot implicitly convert expression (__lambda2) of type
int delegate(int a) nothrow @safe to int delegate(int a) pure
nothrow
This fails:
void main() {
int z;
typeof((int a){return z;}) dg;
dg = (int a) {return z;};
}
Error: cannot implicitly convert expression (__lambda2) of type
int delegate(int a) nothrow @safe to int delegate(int a) pure
nothrow @safe
But I can't make the delegate pure:
dg = (int a)