On Thursday, 14 May 2015 at 00:29:06 UTC, Dennis Ritchie wrote:
Why doesn't the compiler produces an error?
-
import std.stdio;
void main() {
writeln({});
}
-
http://ideone.com/qTZCAd
Somehow reminds me of this lambda:
On Friday, 15 May 2015 at 08:44:41 UTC, Ivan Kazmenko wrote:
Somehow reminds me of this lambda:
https://github.com/Hackerpilot/Idiotmatic-D/blob/master/idiotmatic.d#L127-L128
Maybe it generally blocks for initialization of variables:
On 05/14/2015 03:39 PM, Dennis Ritchie wrote:
On Thursday, 14 May 2015 at 21:55:40 UTC, Alex Parrill wrote:
On Thursday, 14 May 2015 at 00:39:25 UTC, Dennis Ritchie wrote:
On Thursday, 14 May 2015 at 00:33:33 UTC, Brian Schott wrote:
You told it to output a function literal, so it did.
Yes,
On Thursday, 14 May 2015 at 00:39:25 UTC, Dennis Ritchie wrote:
On Thursday, 14 May 2015 at 00:33:33 UTC, Brian Schott wrote:
You told it to output a function literal, so it did.
Yes, but it would be logical to deduce something like:
-
writeln({}); // prints literal[{}]
Or the compiler
On Thursday, 14 May 2015 at 21:55:40 UTC, Alex Parrill wrote:
On Thursday, 14 May 2015 at 00:39:25 UTC, Dennis Ritchie wrote:
On Thursday, 14 May 2015 at 00:33:33 UTC, Brian Schott wrote:
You told it to output a function literal, so it did.
Yes, but it would be logical to deduce something
On Thursday, 14 May 2015 at 22:55:43 UTC, Ali Çehreli wrote:
Yes, it is weird but that value happens to be the address of
the function. Here is another test:
import std.stdio;
void foo() pure nothrow @nogc @safe
{}
void main()
{
void printInfo(T)(T t)
{
writefln(%s %s,
On Thursday, 14 May 2015 at 00:29:06 UTC, Dennis Ritchie wrote:
Why doesn't the compiler produces an error?
-
import std.stdio;
void main() {
writeln({});
}
-
http://ideone.com/qTZCAd
You told it to output a function literal, so it did.
(That or you told it to output a
Turns out that I can put into the function writeln almost any
design language:
-
import std.stdio;
void main() {
writeln( { int n = 5; } );
}
-
http://ideone.com/Rp7gZ2
On Thursday, 14 May 2015 at 00:33:33 UTC, Brian Schott wrote:
You told it to output a function literal, so it did.
Yes, but it would be logical to deduce something like:
-
writeln({}); // prints literal[{}]
Or the compiler will not be able to distinguish the literal from
the ordinary
Why doesn't the compiler produces an error?
-
import std.stdio;
void main() {
writeln({});
}
-
http://ideone.com/qTZCAd
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