On 2018-03-01 12:01:19 +, Steven Schveighoffer said:
Ok, here it is: https://pastebin.com/tKACi488
See lines 81-84 for how I call it. And the problem I have is that
doSubscribe returns "something" I'm not sure what I can do with. But if
the scope ends, my subscription seems to be deleted
On 2/28/18 3:36 PM, Robert M. Münch wrote:
Yes, that's what the docs state. And I can imagin this. Bit this
sentence is a bit hard to understand: "If fun is not a string, unaryFun
aliases itself away to fun." Whatever this means.
It means that it simply becomes the alias you passed in. It
On Wed, Feb 28, 2018 at 09:36:33PM +0100, Robert M. Münch via
Digitalmars-d-learn wrote:
[...]
> Yes, that's what the docs state. And I can imagin this. Bit this
> sentence is a bit hard to understand: "If fun is not a
> string, unaryFun aliases itself away to fun." Whatever this means.
[...]
On 2018-02-28 18:25:37 +, Steven Schveighoffer said:
unaryFun is a template that returns a callable item.
That far I made it too :-)
It could be a struct with an opCall, it could be a function template,
it could be an alias to a real function, it could be a function
pointer, delegate,
On 2018-02-28 18:09:41 +, H. S. Teoh said:
Basically, the `alias f` is a catch-all template parameter that can
bind to basically anything that has a symbol. It's typically used to
bind to functions, delegates, and lambdas.
Aha... ok that makes it a bit more clear. So, if I have:
auto
On 2018-02-28 18:01:50 +, TheFlyingFiddle said:
Testing this with:
auto foo(alias f, A)(auto ref A a) { return f(a); }
I can call foo either like this:
foo!(x => x + x)(1);
or
1.foo!(x => x + x);
but these will give errors
foo(1, x => x + x); //Error
1.foo(x => x + x); // Error
I
On 2/28/18 12:47 PM, Robert M. Münch wrote:
Hi, I'm lost reading some code:
A a;
auto do(alias f, A)(auto ref A _a){
alias fun = unaryFun!f;
return ...
...
}
How is this alias stuff working? I mean what's the type of f? Is it an
anonymous function which then gets checked to be
On Wed, Feb 28, 2018 at 06:47:22PM +0100, Robert M. Münch via
Digitalmars-d-learn wrote:
> Hi, I'm lost reading some code:
>
> A a;
>
> auto do(alias f, A)(auto ref A _a){
> alias fun = unaryFun!f;
> return ...
> ...
> }
>
> How is this alias stuff working? I mean what's the
On Wednesday, 28 February 2018 at 17:47:22 UTC, Robert M. Münch
wrote:
Hi, I'm lost reading some code:
A a;
auto do(alias f, A)(auto ref A _a){
alias fun = unaryFun!f;
return ...
...
}
How is this alias stuff working? I mean what's the type of f?
Is it an anonymous
Hi, I'm lost reading some code:
A a;
auto do(alias f, A)(auto ref A _a){
alias fun = unaryFun!f;
return ...
...
}
How is this alias stuff working? I mean what's the type of f? Is it an
anonymous function which then gets checked to be unary? How is it
recognized in the
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