On 1/29/23 14:19, max haughton wrote:
> it is not trivial to find where the *end* of a
> function is
I suspected as much and did run ...
> objdump
... to fool myself into thinking that 0xc3 was . Well, arguments
e.g. pointer values can have 0xc3 bytes in them. So, yes, I am fooled! :)
Ali
On Sunday, 29 January 2023 at 21:45:11 UTC, Ruby the Roobster
wrote:
I'm trying to do something like
```d
void main()
{
auto d =
*d.writeln;
}
void c()
{
}
```
In an attempt to get the hexadecimal representation of the
machine code of a function. Of course, function pointers
On 1/29/23 13:45, Ruby the Roobster wrote:
> Of course, function pointers cannot be dereferenced.
Since you want to see the bytes, just cast it to ubyte*. The following
function dumps its own bytes:
import std;
void main() {
enum end = 0xc3;
for (auto p = cast(ubyte*)&_Dmain; true;
I'm trying to do something like
```d
void main()
{
auto d =
*d.writeln;
}
void c()
{
}
```
In an attempt to get the hexadecimal representation of the
machine code of a function. Of course, function pointers cannot
be dereferenced. What do?
Furthermore, I would like to be able to
