On Thursday, 8 April 2021 at 18:06:25 UTC, Meta wrote:
On Thursday, 8 April 2021 at 18:01:56 UTC, Meta wrote:
On Thursday, 8 April 2021 at 12:19:29 UTC, WebFreak001 wrote:
```d
string to01String(int[] x) @safe
{
auto conv = x.to!(ubyte[]); // allocates new array, so
later cast to string i
On Thursday, 8 April 2021 at 04:02:26 UTC, Ali Çehreli wrote:
On 4/7/21 8:57 PM, Brad wrote:
auto a = [1,0,1,1,1,0,1,0,1,1,1,1,0];
I want to come out of this with a string that looks like this:
101110100
Me, me, me, me! :)
import std;
void main()
{
auto a = [1,0,1,1,1,0,1,0,1,1
On Thursday, 8 April 2021 at 22:27:38 UTC, Alain De Vos wrote:
So which concrete types do you give for the two auto's.
Like Paul said.
But if you really wanted to type it out:
a is int[], conv is ubyte[] and the map is lazy, so add .array
and it evaluates to char[]
On Thursday, 8 April 2021 at 22:27:38 UTC, Alain De Vos wrote:
So which concrete types do you give for the two auto's.
The first `auto` is the return type of `to!(ubyte[])`--so, it's
`ubyte[]`.
The second `auto` is the return type of `map`. If you look at the
documentation [2], you'll see t
So which concrete types do you give for the two auto's.
On Thursday, 8 April 2021 at 22:02:47 UTC, Alain De Vos wrote:
I resume in the 4 ways presented,
import std;
void main(){
auto a=[1,0,1,1,1,0,1,0,1,1,1,0];
string s = format!"%-(%s%)"(a);
writeln(s);
dchar[12] b = a.map!(to!string).joiner.array;
I resume in the 4 ways presented,
import std;
void main(){
auto a=[1,0,1,1,1,0,1,0,1,1,1,0];
string s = format!"%-(%s%)"(a);
writeln(s);
dchar[12] b = a.map!(to!string).joiner.array;
writeln(b);
auto conv = a.to!(ubyte[]);
On Thu, Apr 08, 2021 at 08:28:44PM +, Alain De Vos via Digitalmars-d-learn
wrote:
> The ascii code of 0 is 48 so I think you can add everywhere 48 (but
> I'm not a specialist)
Why bother with remembering it's 48? Just add '0', like this:
int a = [1, 0, 1, 0, 1, ...];
string s
The ascii code of 0 is 48 so I think you can add everywhere 48
(but I'm not a specialist)
On Thursday, 8 April 2021 at 18:01:56 UTC, Meta wrote:
On Thursday, 8 April 2021 at 12:19:29 UTC, WebFreak001 wrote:
```d
string to01String(int[] x) @safe
{
auto conv = x.to!(ubyte[]); // allocates new array, so
later cast to string is OK
conv[] += '0'; // assume all numbers are 0-9, t
On Thursday, 8 April 2021 at 12:19:29 UTC, WebFreak001 wrote:
```d
string to01String(int[] x) @safe
{
auto conv = x.to!(ubyte[]); // allocates new array, so
later cast to string is OK
conv[] += '0'; // assume all numbers are 0-9, then this
gives the correct result
return (() @trus
On Thursday, 8 April 2021 at 16:45:14 UTC, Jack wrote:
On Thursday, 8 April 2021 at 04:02:26 UTC, Ali Çehreli wrote:
On 4/7/21 8:57 PM, Brad wrote:
auto a = [1,0,1,1,1,0,1,0,1,1,1,1,0];
I want to come out of this with a string that looks like
this: 101110100
Me, me, me, me! :)
i
On Thursday, 8 April 2021 at 04:02:26 UTC, Ali Çehreli wrote:
On 4/7/21 8:57 PM, Brad wrote:
auto a = [1,0,1,1,1,0,1,0,1,1,1,1,0];
I want to come out of this with a string that looks like this:
101110100
Me, me, me, me! :)
import std;
void main()
{
auto a = [1,0,1,1,1,0,1,0,1,1
On Thursday, 8 April 2021 at 03:57:23 UTC, Brad wrote:
I am trying to take an array and convert it to a string. I
know that Split will let me easily go the other way. I
searched for the converse of Split but have not been able to
locate it. I can think of two brute force methods of doing
th
On 4/7/21 8:57 PM, Brad wrote:
auto a = [1,0,1,1,1,0,1,0,1,1,1,1,0];
I want to come out of this with a string that looks like this:
101110100
Me, me, me, me! :)
import std;
void main()
{
auto a = [1,0,1,1,1,0,1,0,1,1,1,1,0];
string s = format!"%-(%s%)"(a);
writeln(s);
}
Al
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