On 14/10/2010 18:14, Andrej Mitrovic wrote:
Should the order in which you implement interfaces have an effect in
your code?
No.
It seems to be that way when you have two functions with
thesame name in the different interfaces.
If they are normal interface functions, then if they have the s
Jonathan M Davis:
> I believe that you'd have to
> do something like Foo.run() and Bar.run() to call run(). I'd have to check
> TDPL
> to be completely sure of the syntax though.
I think that's a compiler bug, regardless what the TDPL-Bible says :-)
Bye,
bearophile
On Thursday, October 14, 2010 10:14:25 Andrej Mitrovic wrote:
> Should the order in which you implement interfaces have an effect in your
> code? It seems to be that way when you have two functions with the same
> name in the different interfaces. Here's an example:
>
> import std.stdio : writeln;
Should the order in which you implement interfaces have an effect in your code?
It seems to be that way when you have two functions with the same name in the
different interfaces. Here's an example:
import std.stdio : writeln;
interface Foo
{
final void run() { writeln("foo"); }
}
interfa
