I'd typed the response before it displayed your reply that
already answered the question. =) Sadly Array!bool doesn't seem
to be memoizable, I assume memoization only sees container
information or something like that. How would I go about creating
an index accessible array using a struct of bit
On Tuesday, 15 May 2012 at 20:50:27 UTC, ixid wrote:
So if that will not work how would I efficiently copy an array
of
BitArray? Looping through each bit is very slow. An array of
bool
arrays is fine but I want to try to reduce the memory needed for
memoization of an algorithm.
That wouldn't
So if that will not work how would I efficiently copy an array of
BitArray? Looping through each bit is very slow. An array of bool
arrays is fine but I want to try to reduce the memory needed for
memoization of an algorithm.
On Tuesday, 15 May 2012 at 20:26:12 UTC, ixid wrote:
Sorry I made a typo in the second, it should be test2[0][0].
I'm using std.bitmanip in D2.
Aha, I see! I'm somewhat surprised, normally I just use
Array!bool.
Well, you can look in the source to see some of how it works:
https://github.com/D
On Tuesday, 15 May 2012 at 20:44:16 UTC, Chris Cain wrote:
test2[0] = 1;
and of course I mean test2[0][0] ... copy-pasta mistake :-)
On Tuesday, 15 May 2012 at 20:16:28 UTC, Chris Cain wrote:
On Tuesday, 15 May 2012 at 19:23:31 UTC, ixid wrote:
Not sure if this is a bug or just rather counter-intuitive:
BitArray test;
test.length = 7;
BitArray test2 = test.dup;
test2[0] = 1;
This is fine, test is not modified.
BitArray tes
On Tuesday, 15 May 2012 at 19:23:31 UTC, ixid wrote:
Not sure if this is a bug or just rather counter-intuitive:
BitArray test;
test.length = 7;
BitArray test2 = test.dup;
test2[0] = 1;
This is fine, test is not modified.
BitArray test[7];
foreach(ref i;test)
i.length = 7;
BitArray[7] test
