On Thursday, 15 March 2018 at 15:41:54 UTC, Robert-D wrote:
Why something like this doesn't compile (with or without the
cast on bb.dup)?
struct S {
string[string] aa;
S dup() inout pure {
return S(cast(string[string]) aa.dup);
}
}
struct SS {
S[] bb;
SS dup()
On Thursday, 15 March 2018 at 13:18:38 UTC, Simen Kjærås wrote:
On Thursday, 15 March 2018 at 12:00:08 UTC, Robert-D wrote:
I want the function to create a mutable copy from a const or a
imutable
Like this:
void main() {
const S s = S(["": ""]);
S b = s.dup();
}
How can i do that?
On Thursday, 15 March 2018 at 12:00:08 UTC, Robert-D wrote:
I want the function to create a mutable copy from a const or a
imutable
Like this:
void main() {
const S s = S(["": ""]);
S b = s.dup();
}
How can i do that?
In that case, the problem is that you also have to .dup the aa:
On Thursday, 15 March 2018 at 11:33:49 UTC, Simen Kjærås wrote:
On Thursday, 15 March 2018 at 11:18:48 UTC, Robert-D wrote:
[...]
This is where things go wrong:
[...]
'inout' means that this function can keep the const, immutable
or mutable status of the type on which the function is
On Thursday, 15 March 2018 at 11:18:48 UTC, Robert-D wrote:
struct S {
string[string] aa;
S dup() inout pure {
return S(aa);
}
}
void main() {
auto s = S(["": ""]);
s.dup();
}
Result:
Error: cannot implicitly convert expression this.aa of type
