Re: scope exit in mixin template

2014-06-08 Thread Byron via Digitalmars-d-learn
On Sun, 08 Jun 2014 19:44:12 +, monarch_dodra wrote: > On Sunday, 8 June 2014 at 18:28:25 UTC, Byron wrote: >> void c_free(bar* b) { b = null; } > > Heads up: This code does nothing. You are passing the pointer by value, > so "b = null;" will have no effect at the end of the call. > Use pass

Re: scope exit in mixin template

2014-06-08 Thread monarch_dodra via Digitalmars-d-learn
On Sunday, 8 June 2014 at 18:28:25 UTC, Byron wrote: void c_free(bar* b) { b = null; } Heads up: This code does nothing. You are passing the pointer by value, so "b = null;" will have no effect at the end of the call. Use pass by ref: void c_free(ref bar* b) { b = null; }

Re: scope exit in mixin template

2014-06-08 Thread monarch_dodra via Digitalmars-d-learn
On Sunday, 8 June 2014 at 18:48:03 UTC, monarch_dodra wrote: Mixin templates can only insert declarations, not arbitrary code. When it sees "scope", it's expecting it to be the attribute, not the declaration. To add to that, if you want to mixin arbitrary code, then you can use a string mixin

Re: scope exit in mixin template

2014-06-08 Thread monarch_dodra via Digitalmars-d-learn
On Sunday, 8 June 2014 at 18:28:25 UTC, Byron wrote: Can we not use scope(..) in a mixin template? struct bar {} bar* c_make() { return new bar(); } void c_free(bar* b) { b = null; } mixin template Foo() { auto b = c_make; scope(exit) if(b) c_free(b); } void main() { mixin Foo; } I get