On Wednesday, 21 October 2020 at 16:38:34 UTC, Ferhat Kurtulmuş
wrote:
ş
UTF-8: ÅŸ
Numeric: ş
Ansi: ÅŸ
√
On Wednesday, 21 October 2020 at 14:03:54 UTC, DMon wrote:
On Wednesday, 21 October 2020 at 13:04:40 UTC, Ferhat Kurtulmuş
wrote:
import std.range;
import std.stdio;
void main(){
auto source = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10];
auto chunks = chunks(source, 2);
writeln(chunks[0]); //
On Wednesday, 21 October 2020 at 13:04:40 UTC, Ferhat Kurtulmuş
wrote:
import std.range;
import std.stdio;
void main(){
auto source = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10];
auto chunks = chunks(source, 2);
writeln(chunks[0]); // [1, 2]
foreach(c; chunks)
writeln(c[1]);
}
An
On Wednesday, 21 October 2020 at 13:43:51 UTC, matheus wrote:
foreach (i,j;a){
if(i%2==0){ write(j, ", ");}
}
Thank you, matheus. for each on the list.
On Wednesday, 21 October 2020 at 12:06:00 UTC, drug wrote:
There are two other way:
...
// using foreach
foreach (i; 0..a.length)
write(a[i], ", ");
...
Yes you can use foreach, but in this case will not act the way
the OP wanted. In his for loop example the "i" is incremented
On Wednesday, 21 October 2020 at 11:55:54 UTC, DMon wrote:
What is the simplest way to output every nth element of an
array?
I can do it using a for loop:
void main()
{
int[5] a = [1,2,3,4,5];
for (int i = 0 ; i <= 4 ; i += 2)
{
writeln(a[i]);
}
}
Basically, I am wonde
On Wednesday, 21 October 2020 at 12:06:00 UTC, drug wrote:
There are two other way:
Thanks, drug.
stride was what I was looking for.
There are two other way:
```D
import std;
void main()
{
int[] a = [ 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 ];
// using foreach
foreach (i; 0..a.length)
write(a[i], ", ");
writeln;
// using stride
writeln(stride(a, 2));
}
```
What is the simplest way to output every nth element of an array?
I can do it using a for loop:
void main()
{
int[5] a = [1,2,3,4,5];
for (int i = 0 ; i <= 4 ; i += 2)
{
writeln(a[i]);
}
}
Basically, I am wondering if I missed something.
