In the following example from the documentation, are strings
concatenated at compile time?
template foo(string s) {
string bar() { return s ~ betty; }
}
void main() {
writefln(%s, foo!(hello).bar()); // prints: hello betty
}
On Thursday, 1 May 2014 at 10:42:36 UTC, Unwise wrote:
In the following example from the documentation, are strings
concatenated at compile time?
template foo(string s) {
string bar() { return s ~ betty; }
}
void main() {
writefln(%s, foo!(hello).bar()); // prints: hello betty
}
I
On Thu, 01 May 2014 11:12:41 +
anonymous via Digitalmars-d-learn digitalmars-d-learn@puremagic.com
wrote:
On Thursday, 1 May 2014 at 10:42:36 UTC, Unwise wrote:
In the following example from the documentation, are strings
concatenated at compile time?
template foo(string s
Jonathan M Davis:
If you want it to be guaranteed, you'd do something like
template foo(string s)
{
enum foo = s ~ betty;
}
A more general solution is to wrap the concatenation with a call
to:
alias ctEval(alias expr) = expr;
Use:
string bar() { return ctEval!(s ~ betty); }
Bye,
