On 2012-10-08 21:40, Timon Gehr wrote:
The original behaviour is to be expected and the workaround exploits a
compiler bug.
The correct way to get rid of the compile error is:
void foo(inout(int)[] arr){
auto a = { const b = arr[0]; } // or int b = arr[0];
}
Why can't "auto" work there?
On 10/05/2012 04:09 PM, Ali Çehreli wrote:
...
This workaround makes the compiler happy:
void foo (inout(int)[] arr)
{
auto a = (inout int) { auto b = arr[0]; };
}
But probably not what you want. :/
IIRC, inout has bugs and incomplete implementation. I think this should
be in the bug dat
On 2012-10-05 16:09, Ali Çehreli wrote:
This workaround makes the compiler happy:
void foo (inout(int)[] arr)
{
auto a = (inout int) { auto b = arr[0]; };
}
But probably not what you want. :/
IIRC, inout has bugs and incomplete implementation. I think this should
be in the bug database.
On 2012-10-05 16:09, Ali Çehreli wrote:
This workaround makes the compiler happy:
void foo (inout(int)[] arr)
{
auto a = (inout int) { auto b = arr[0]; };
}
But probably not what you want. :/
IIRC, inout has bugs and incomplete implementation. I think this should
be in the bug database.
On Thu, 04 Oct 2012 09:49:48 -0400, Jacob Carlborg wrote:
void foo (inout int[] arr)
{
auto a = { auto b = arr[0]; };
}
void main ()
{
auto a = [3, 4, 5];
foo(a);
}
Compiling the above code with DMD 2.060 results in the following error
message:
Error: variable main.foo.__la
On 10/04/2012 11:30 PM, Jacob Carlborg wrote:
On 2012-10-04 16:18, Ali Çehreli wrote:
inout is like a template on 'mutable', const, and immutable; but it need
not be applied to templates. Here is a simple example that transfers the
mutability to the return type:
I do think I understand how "
On 2012-10-04 16:18, Ali Çehreli wrote:
inout is like a template on 'mutable', const, and immutable; but it need
not be applied to templates. Here is a simple example that transfers the
mutability to the return type:
I do think I understand how "inout" works, or at least I thought. I
don't u
On 2012-10-04 16:09, Jesse Phillips wrote:
IIRC, inout must be applied to the return type too, and it only works in
templates.
What? The whole point of "inout" is to NOT have to use templates since
the compiler will generate the same code anyway.
http://dlang.org/function.html#inout-functio
On 10/04/2012 07:09 AM, Jesse Phillips wrote:
On Thursday, 4 October 2012 at 13:55:39 UTC, Jacob Carlborg wrote:
void foo (inout int[] arr)
{
auto a = { auto b = arr[0]; };
}
void main ()
{
auto a = [3, 4, 5];
foo(a);
}
Compiling the above code with DMD 2.060 results in the following error
mes
On Thursday, 4 October 2012 at 13:55:39 UTC, Jacob Carlborg wrote:
void foo (inout int[] arr)
{
auto a = { auto b = arr[0]; };
}
void main ()
{
auto a = [3, 4, 5];
foo(a);
}
Compiling the above code with DMD 2.060 results in the
following error message:
Error: variable main.foo._
void foo (inout int[] arr)
{
auto a = { auto b = arr[0]; };
}
void main ()
{
auto a = [3, 4, 5];
foo(a);
}
Compiling the above code with DMD 2.060 results in the following error
message:
Error: variable main.foo.__lambda1.b inout variables can only be
declared inside inout functi
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