On Wednesday, December 21, 2016 23:18:29 Nordlöw via Digitalmars-d-learn
wrote:
> Do you have any clue on how to most easily find detect whether a
> SymbolExpression is the last reference to that symbol in the
> scope of the symbol definition, Jonathan?
Sorry, but my knowledge of dmd's internals
On 12/21/2016 02:59 PM, Nordlöw wrote:
On Wednesday, 21 December 2016 at 21:02:17 UTC, Ali Çehreli wrote:
void f(Rs...)(Rs ranges)
{
import std.functional: forward;
g(forward!ranges);
Interesting. How does this differ from std.algorithm.mutation.move()
when R.length is 1?
Why do we ha
On Wednesday, 21 December 2016 at 23:11:02 UTC, Nordlöw wrote:
Given that ref isn't involved, assuming that nothing else
after the call to g references ranges, the compiler should
move the values in ranges when it calls g
Yes, DMD should automatically convert the last reference of a
value exp
On Wednesday, 21 December 2016 at 21:09:41 UTC, Jonathan M Davis
wrote:
Given that ref isn't involved, assuming that nothing else after
the call to g references ranges, the compiler should move the
values in ranges when it calls g, so I would have hoped that
the compiler would then allow you to
On Wednesday, 21 December 2016 at 21:02:17 UTC, Ali Çehreli wrote:
void f(Rs...)(Rs ranges)
{
import std.functional: forward;
g(forward!ranges);
Interesting. How does this differ from
std.algorithm.mutation.move() when R.length is 1?
Why do we have both `move` and `forward`, then?
On Wednesday, December 21, 2016 20:27:47 Nordlöw via Digitalmars-d-learn
wrote:
> If I have a variadic function
>
> f(Rs...)(Rs ranges)
> {
> g(ranges);
> }
>
> that calls
>
> g(Rs...)(Rs ranges)
> {
> // use ranges
> }
>
> and all or some of the elements in `ranges` are non-copyable can
On 12/21/2016 12:27 PM, Nordlöw wrote:
If I have a variadic function
f(Rs...)(Rs ranges)
{
g(ranges);
}
that calls
g(Rs...)(Rs ranges)
{
// use ranges
}
and all or some of the elements in `ranges` are non-copyable can I
somehow move them at the call of `g` inside of `f`.
I've tried
If I have a variadic function
f(Rs...)(Rs ranges)
{
g(ranges);
}
that calls
g(Rs...)(Rs ranges)
{
// use ranges
}
and all or some of the elements in `ranges` are non-copyable can
I somehow move them at the call of `g` inside of `f`.
I've tried
f(Rs...)(Rs ranges)
{
import std.a
