On Tuesday, 31 May 2016 at 06:40:31 UTC, Era Scarecrow wrote:
On Tuesday, 31 May 2016 at 05:31:59 UTC, chmike wrote:
My conclusion is that rebindable is not a satisfying solution
to have mutable references to immutable objects.
I don't understand the rationale of these immutable
references. I
On Tuesday, 31 May 2016 at 05:31:59 UTC, chmike wrote:
My conclusion is that rebindable is not a satisfying solution
to have mutable references to immutable objects.
I don't understand the rationale of these immutable references.
It is too constraining.
I still don't know why you're trying
On Monday, 30 May 2016 at 21:32:46 UTC, Alex Parrill wrote:
On Monday, 30 May 2016 at 10:09:19 UTC, chmike wrote:
Why can't info() return a Rebindable!(immutable(InfoImpl)) ?
What do you mean? `info` returns an `immutable(InfoImpl)`, not
a `Rebindable!(immutable(InfoImpl))`. Rebindable doesn
On Monday, 30 May 2016 at 10:09:19 UTC, chmike wrote:
This code compile, but array appending doesn't work
alias Rebindable!(immutable(InfoImpl)) Info;
class InfoImpl
{
void foo() {}
static immutable(InfoImpl) info()
{
__gshared immutable InfoImpl x = new immutable InfoI
This code compile, but array appending doesn't work
alias Rebindable!(immutable(InfoImpl)) Info;
class InfoImpl
{
void foo() {}
static immutable(InfoImpl) info()
{
__gshared immutable InfoImpl x = new immutable InfoImpl;
return x;
}
}
void main()
{
Info
Oops, the duplicate alias instruction and main are copy past
error. It looks like the code was already too complex for me. ;)
Here is the code I tested
import std.typecons;
Rebindable!(immutable TestImpl) Test;
class TestImpl
{
void foo() {}
Test test() { __gshared x = new immuta
Hello,
here is a program stripped down to the minimum code that doesn't
compile
import std.typecons;
Rebindable!(immutable TestImpl) Test;
Rebindable!(immutable TestImpl) Test;
class TestImpl
{
void foo() {}
Test test() { __gshared x = new immutable TestImpl; return
rebindable
