Simen Kjaeraas:
Both 5 and 9 in the second example are integers (int). When you
divide
one int by another, the result is an int, and hence (5/9) is 0.
Yes, smarter languages (like Pascal..., but also Python, Ada,
etc) have two different division operators to avoid such silly C
semantics, th
Dne 2.5.2013 20:14, Carlos napsal(a):
I have this code :
import std.stdio;
import std.c.stdlib;
void main()
{
int fahr;
write("F\tC\n");
for (fahr = 0; fahr <= 300; fahr = fahr + 20)
write(fahr, "\t", (5.0/9.0)*(fahr-32), "\n");
write("Done!\n");
exit (0);
}
Which works. but if I change the "5
On 2013-05-02, 20:14, Carlos wrote:
I have this code :
import std.stdio;
import std.c.stdlib;
void main()
{
int fahr;
write("F\tC\n");
for (fahr = 0; fahr <= 300; fahr = fahr + 20)
write(fahr, "\t", (5.0/9.0)*(fahr-32), "\n");
write("Done!\n");
exit (0);
}
Which works. but if I change the "5.
I have this code :
import std.stdio;
import std.c.stdlib;
void main()
{
int fahr;
write("F\tC\n");
for (fahr = 0; fahr <= 300; fahr = fahr + 20)
write(fahr, "\t", (5.0/9.0)*(fahr-32), "\n");
write("Done!\n");
exit (0);
}
Which works. but if I change the "5.0" for "5" I get cero on the
celsius s
