Why does g(cs) compile but not G(cs)?
Thanks,
Dan
struct S{}
void g(ref S i) {}
void g(const ref S i) {}
void G(T)(ref T i) {}
void G(T)(const ref T i) {}
void main() {
S s;
const(S) cs;
g(s);
g(cs);
G(s);
// Error: template p.G matches more than one template
declaration,
On 11/06/2012 09:18 AM, Dan wrote:
Why does g(cs) compile but not G(cs)?
Thanks,
Dan
struct S{}
void g(ref S i) {}
void g(const ref S i) {}
void G(T)(ref T i) {}
void G(T)(const ref T i) {}
void main() {
S s;
const(S) cs;
g(s);
g(cs);
G(s);
// Error: template p.G matches more than one
On Tuesday, 6 November 2012 at 18:34:04 UTC, Ali Çehreli wrote:
Because in the case of cs, T is 'const(S)', matching the
following two instantiations:
1) ref const(S) i
2) const ref const(S) i
The second line has a redundant const. So, they end up having
the same signature.
Ali
Oh -
